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What is the prime factorization of 176 using exponential notation?
Prime factors in exponent form: 2^4 * 11
What is the prime factorization of 441 using exponents when repeated factors appear?
441 = 32 x 72
What is the prime factorization of 1701 using exponents when repeated factors appear?
35 x 7 = 1701
Prime factorization for 90 using exponent?
The prime factors of 90 in exponential form are 21 x 32 x 51.
What is the prime factorization of 792 using exponents when repeated factors appear?
23 x 32 x 11 = 792
How do you write the product using an exponent?
Exponents are just shorthand for repeated factors.2 x 2 x 2 x 3 x 3 x 3 = 21623 x 33 = 216
Numbers written using exponents that represent repeated multiplication?
powers, or exponent
What are the prime factors of 81 using an exponent?
34 = 81
What is prime factorization for 165 using exponent?
As a product of its prime factors: 3*5*11 = 165 none of which have exponents
write each power as a product of repeated factors. then evaluate the power?
Power of a number can be evaluated using repeated multiplication of the number by itself. For example, 5 to the third power can be evaluated using multiplication of 5 by itself for three times as shown below. 53 = 5 x 5 x 5 The power or exponent of a number says how many times a number has to be multiplied repeatedly by itself.
What is an example of using a repeated factor for math?
When expressing a number as a product of its prime factors as for example 2*2*2*2*2*2 = 64
How to write repeated multiplication of a factor by using an exponent?
To write repeated multiplication in an exponential notation, you should write the number that has to be multiplied as the base. Count the number of times that the number is used.
How do you do prime factorization using exponents?
1) Find the prime factors. For example, 12 = 2 x 2 x 3. 2) Replace all repeated prime factors by a single copy of the prime factor, and an exponent that specifies how often the prime factor is repeated. For example, 2 x 2 x 3 = 22 x 3.
What are the factors of 411 using exponents when repeated factors appear?
3 x 137 = 411
Write each product using and exponent...9 x 9?
92=81
How do you solve -8 cubed using exponents and as a product of repeated factors?
To solve -8 cubed using exponents, you raise -8 to the power of 3, which can be written as (-8)³. This equals -8 * -8 * -8, or -512. As a product of repeated factors, you can express it as -8 * -8 * -8 = (-1) * 2 * 2 * 2 * 2 * 2 * 2 * 2 = -512.
Can the prime factorization 2x5x13 be written using exponents?
No, none of the factors are repeated.
