The roots of the equation are -4 and 3. Simplest solution is (x +4 )(x - 3) which multiplies out as x^2 + x - 12 = 0
Yes because rearranging it into the form of 3x2-10x+5 = 0 makes the discriminant of the quadratic equation greater than zero which means it will have two different solutions. Solving the equation by means of the quadratic formula gives x as being 2.721 or 0.613 both corrected to 3 decimal places.
That's not an equation - it doesn't have an equal sign. Assuming you mean 2x2 - 3x - 90 = 0, you can find the solution, or usually the two solutions, of such equations with the quadratic formula. In this case, replace a = 2, b = -3, c = -90.
To find the zeros of this quadratic function, y= 3x^2 + 6x - 9, we must equal y to 0. So we have the quadratic equation: 3x^2+6x-9 = 0, where a = 3, b = 6, and c = -9 The quadratic formula: x = [-b ± √(b^2 - 4ac)]/(2a) substitute what you know into this formula; x = [-6 ± √(6^2 - 4 x 3 x -9)]/(2 x 3) x = [-6 ± √(36 +108)]/6 x = (-6 ± √144)/6 x = (-6 ± 12)/6 Simplify: mulyiply by 1/6 both the numerator and the denominator; x = -1 ± 2 x = -1 + 2 or x = -1 - 2 x = 1 or x = -3 So solutions are -3 and 1. If you check the answers by plugging them into the equation, you will see that they work.
There is a new method, called Diagonal Sum Method, that quickly and directly give the 2 roots without having to factor the equation. The innovative concept of this method is finding 2 fractions knowing their sum (-b/a) and their product (c/a). It is fast, convenient and is applicable to any quadratic equation in standard form ax^2 + bx + c = 0, whenever it can be factored. If it fails to find answer, then the equation is not factorable, and consequently, the quadratic formula must be used. So, I advise you to proceed solving any quadratic equation in 2 steps. First, find out if the equation can be factored? How?. Use this new method to solve it. It usually takes fewer than 3 trials. If its fails then use the quadratic formula to solve it in the second step. See book titled:" New methods for solving quadratic equations and inequalities" (Trafford Publishing 2009)
Without an equality sign and not knowing the plus or minus values of 3x and 3 the information given can't be considered to be a quadratic equation.
The quadratic formula can be used to solve an equation only if the highest degree in the equation is 2.
y=2(x-3)+1
This does not factor to whole numbers. You need to use the quadratic formula... -b+-sqrt[b2-4(a)(c)] / 2a Your equation is this [below]. Identify what a,b and c equals and put it into your quadratic formula. 3m2-88 a=3 b=0 c=-88 when you work this out you get two answers but they are not whole numbers. your answers are 5.416 an -5.416
I suggest you use the quadratic formula. In this case, a = 1, b = 5, c = 3.
It is a quadratic equation that can be solved by using the quadratic equation formula whereas x = -9.321825 or x = 0.321825 both given to 6 decimal places
If you mean: 11x2-34x+3 = 0 then the solutions are x = 1/11 and x = 3 by completing the square or using the quadratic equation formula
By using the quadratic equation formula: (4x+1)(x-3) = 0
Using the quadratic equation formula: x = -3 - the square root of 3 or x = -3 + the square root of 3
Use the quadratic formula, with a = 1, b = -3, c = 2.
56w2-17w-3 = (8w+1)(7w-3) Using the quadratic equation formula helps.
To solve the quadratic equation, S^2 + 4S - 21 = 0, you can factor the expression or use the quadratic formula. Factoring, we can rewrite it as (S-3)(S+7) = 0. This means that either S-3 = 0 or S+7 = 0. Solving for S in each case gives S = 3 or S = -7 as the solutions to the equation.
Roots, zeroes, and x values are 3 other names for solutions of a quadratic equation.