3 is a factor and dividing by 3 gives
x + 15 = 8x
3x
3(x2 + 3x + 1)
Yes, 5 is a factor of 7565 because 7565 is divisible by 5.
3x2 + 10x + 3 = (x + 3)(3x + 1).
9x2 + 6x + 1 = 9x2 + 3x + 3x + 1 = 3x(3x + 1) + 1(3x + 1) = (3x + 1)(3x + 1) or (3x +1)2
(3x + 4)(3x + 4)
Let the symbol ^ mean "to the power" Then 9x^2 + 24x + 16 = (3x + 4)(3x +4) = (3x + 4)^2
3x(x - 2)(x - 4)
3x - 24x + 5 + 3 = -21x + 8
(3x - y)(3x - 5y) and (2x + 1)(2x + 11)
3x
3x(2x + 1)
3x(x - 8)
3x
3x^(2) - 24x + 48 Factor out '3' 3(x^(2) - 8x + 16) 3(x - 4)(x - 4) Fullt factored.
3x3-18x2+24x=3x(x2-6x+8)=3x(x-4)(x-2)
Presumably you mean: 9x2+24x+16? (3x+4)(3x+4)