3(x2 + 3x + 1)
5x^3(3x + 2)
9x2 + 6x + 1 = 9x2 + 3x + 3x + 1 = 3x(3x + 1) + 1(3x + 1) = (3x + 1)(3x + 1) or (3x +1)2
(x - 8)(3x + 4)
In one bracket, write 16 times the square root of 2 minus 3x. In the other one, write 16 times the square root of 2 plus 3x.
6x2 + 10x = 2x*(3x + 5)
The factors are [3x + 5 - 2*sqrt(10)] and [3x 5 + 2*sqrt(10)].
6x2 + 10x = 2x(3x + 5)
-3.
2x(3x + 5)
It is: 3x*(x+7)
(3x - y+ 2)(3x + y + 2)
3(x2 + 3x + 1)
(3x + 1)(x + 5)
(x + 5)(3x + 1)
If that's -18y2, the answer is (3x - 2y)(x + 9y)
(3x + 3y)(x + y) = 3(x + y)2