Q: How do you Factor 3X squared plus 10X plus 3?

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3(x2 + 3x + 1)

5x^3(3x + 2)

9x2 + 6x + 1 = 9x2 + 3x + 3x + 1 = 3x(3x + 1) + 1(3x + 1) = (3x + 1)(3x + 1) or (3x +1)2

(x - 8)(3x + 4)

In one bracket, write 16 times the square root of 2 minus 3x. In the other one, write 16 times the square root of 2 plus 3x.

Related questions

6x2 + 10x = 2x*(3x + 5)

The factors are [3x + 5 - 2*sqrt(10)] and [3x 5 + 2*sqrt(10)].

6x2 + 10x = 2x(3x + 5)

-3.

2x(3x + 5)

It is: 3x*(x+7)

(3x - y+ 2)(3x + y + 2)

3(x2 + 3x + 1)

(3x + 1)(x + 5)

(x + 5)(3x + 1)

If that's -18y2, the answer is (3x - 2y)(x + 9y)

(3x + 3y)(x + y) = 3(x + y)2