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Since 2p is a factor of 6p^3, it is automatically the GCF.

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Related questions

What is the GCF of the monomials 6p3 and 2p?

The GCF is 2p.


What is the greatest common factor of 5p and 20pp?

The greatest common factor of 5p and 20pp is 5p.Factors of 20pp can be written out as 1p and 20p, 2p and 10p, 4p and 5p.Factors of 5p can be written as 1 and 5p or 1p and 5.The highest factor they both have in common is 5p.


What is 4p2-4p-3 factor completely?

(2p - 3)(2p + 1)


How do you factor p squared - 2p?

p2-2p = p(p-2) when factored


Factor 2p plus 11p plus 5?

2p + 11p + 5 = 13p + 5 which does not factor. If the expression had been 2p2 + 11p + 5 then this can be factored, 2p2 + 11p + 5 = (2p + 1)(p + 5)


How do you factor 3p squared - 2p - 5?

3p2-2p-5 = (3p-5)(p+1) when factored


What is the answer to 6p 3 by factorising?

If we have 6p+3 The common factor to both 6p and 3 is 3. If we take this out the front of brackets we get 3(2p+1)


How do you factor 4p plus 10q?

2(2p + 5q)


How do you rearrange a mathematics equation such as 2pr plus 6qs-3qr-4ps?

This is an expression, not an equation. To rearrange it, you arrange the expression so that the first set of terms have a variable (letter) in common. Arrange the rest so that they follow a similar patter (see working below). Then factorise. 2pr + 6qs - 3qr - 4ps. Select r to be the common variable for the first two terms. So 2pr - 3qr + 6qs - 4ps You will see that terms (now numbered) 3 and 4 have s in common. But, while with the first two, the term with p comes before the term with q, with 3 and 4, it is the other way around. So swap terms 3 and 4. 2pr - 3qr - 4ps + 6qs Common factor of terms 1 and 2 = r, common factor of terms 3 and 4 = s: r(2p - 3q) - 2s(2p - 3q) and then (2p - 3q) is a common factor so (2p - 3q)(r - 2s)


What is the factor of 2p2 5p 3?

If all the terms are positive then it is: (2p+3)(p+1)


How do you factor 10p3-25p2 plus 4p-10?

(2p - 5)(5p^2 + 2)


-4p+(-2)+2p+3?

True Observe the following: 5x + 5y + 3z = 5(x + y) + 3z The first two terms could be factored because they shared a common factor of 5, but the third term did not -- not all terms need to share a common factor to use the grouping method.