A 10-bit binary number can represent (2^{10}) different combinations. This is because each bit can be either 0 or 1, leading to (2) choices for each of the (10) bits. Therefore, (2^{10} = 1024) different combinations can be represented by 10 bits.
1000
In a binary system, each bit can be either 0 or 1. Therefore, for 5 bits, the total number of combinations can be calculated as (2^5). This results in 32 different combinations, ranging from 00000 to 11111.
There are 16 decimal numbers that can be represented by 4-bits.
26 = 64
With two bits, there are (2^2) possible combinations, which equals 4. The combinations are: 00, 01, 10, and 11. Each bit can be either 0 or 1, leading to these four distinct configurations.
4 bits. 24 = 16, so you have 16 different combinations.4 bits. 24 = 16, so you have 16 different combinations.4 bits. 24 = 16, so you have 16 different combinations.4 bits. 24 = 16, so you have 16 different combinations.
1000
2
2^12=4096
n2 -1
24 = 16
The number of distinct combinations that can be created with n bits is 2n.
In a binary system, each bit can be either 0 or 1. Therefore, for 5 bits, the total number of combinations can be calculated as (2^5). This results in 32 different combinations, ranging from 00000 to 11111.
Binary bits are necessary to represent 748 different numbers in the sense that binary bits are represented in digital wave form. Binary bits also have an exponent of one.
There are 16 decimal numbers that can be represented by 4-bits.
1 byte is 8 bits. That's 8 1s or 0s. 2 bytes is 8*2=16 bits (1s/0s). That is 2^16=65536 possibilities. Therefore, there are 65,536 different combinations with 2 bytes.
26 = 64