Algebraically, X = integers.
X + (X + 1) = 237
gather all terms on the left
2X + 1 = 237
subtract 1 from each side
2X = 236
divide both sides integers by 2
X = 118
--------------so,
X + 1 = 119
----------------so,
The two consecutive integers that = 237 are
118 and 119
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There are two consecutive even integers. The numbers are 118 and 120.
Divide the sum of the two consecutive odd integers by 2: 156/2=78. The two consecutive odd integers will be one more and one less than 78, so the smaller will be 77 and the larger will be 79.
Divide the sum of the three consecutive odd integers by 3: -3 /3 = -1. The smallest of these integers will be two less than -1 and the largest will be two more than -1, so the three consecutive odd integers will be -3, -1, and +1.
28,30
The integers are 20 and 22.