The three composite numbers are 28, 30 and 32. Their sum is 90.
Well, honey, if we're following the pattern of subtracting 2, then 4, then 8, the next three numbers would be 109, 97, and 73. But hey, who am I to tell you what to do? You do you, boo.
7, 9, 11
the answer is 120 because the first three prime numbers are 2,3,5 and the first three composite numbers are 4,6,8.
Three composite numbers are 1 3 6
the next three numbers are 180 540 and 1620=)
The difference between the successive numbers is 4. so the next three numbers could be 4, 0 and -4.
Adding 0.6 each time gives 5.2, 5.8 and 6.4 as the next three numbers.
There are no numbers specified therefore this question is unanswerable.
hrgewgyfewrjhurygufyrhyg4uygtyutu4yrktuyttyutyu34yt4hgjheuiu43tuuykuyuhriegquuryqurhuqyqhqb yurrfjynvqnuqqpfp4ct3qtqumc22mutcwvnoov28on24v89yv8nno2v5cu
6,4,2 0
36,49,63
Assuming the sequence of numbers declines by 5 each time, the next three numbers would be 40, 35 and 30.
It appears as if the pattern is doubling, therefore the next three numbers are 16, 32, and 64.
70, 112, 168
The numbers with only three factors are squares of prime numbers.
What numbers would you like to be the next three? It is possible to find a polynomial of order 5 that will fit these three numbers and ANY other three numbers. For example, using the positin to value rule given by Un= -112.275n5 + 1,966.25n4 - 12,744.625n3 + 37,416.25n2 - 48,979.6 + 36,525 I can fit the numbers 1, 2 and 3 as the next three. So there are infinitely many possible answers to the question. Using the simplest rule, although the question does not require that, gives Un = 70n + 2001 and that requires the next three numbers to be 2281, 2351, 2421.