37
-- "The sum of a two-digit number" is unclear. I took it to mean"The sum of the digits of a two-digit number."-- "... the product ?" is unclear. Are you looking for the product of the two digits,or the product of the forward and backward numbers ?-- It's not possible to write a number whose two digits sum to 12 and whosereverse exceeds it by 25. The tens digit would have to be 4.611... and the unitsdigit would have to be 7.388... .Then(4.611...) + (7.388...) = 12(46.111...) + (7.388...) = 53.5(73.888...) + (4.611...) = 78.5Difference = 25So, the number can't be written, but ...The product of its two digits is 34.071 (rounded)The product of the forward and reverse numbers is 4,199.75 (rounded)
3 and 7 are the prime numbers because they cannot be divided by any number other than themselves and 1because 3+7 = 10 (Sum)and 3x7 = 21 (Product)
Any two odd numbers will have an odd product and an even sum.
Usually a question like this should be something like 200 or something it would be about 225 for half of 50
They are: 7 and 12
1/x + 1/y = (y+x)/xy But y + x = sum = 150, and xy = product = 40 So sum of reciprocals = 150/40 = 3.75
A single number cannot have a sum or a product - a sum or product is used to compare two or more numbers.
The sum of four and the product of three and a number xxxx.
10 and 15
150
The product is the answer to a multiplication sum. A single number cannot have a product.
150*6800/(150+6800) = 1020000/6950 = 146.7626 (to 4 dp)
I guess you mean: what two numbers sum to 31 and multiply together to get 150? 6 & 25 (6 + 25 = 31, 6 x 25 = 150)
A number can have only one sum: itself. And it cannot have a product without another number!
150
25 and 6.