All multiples of the lowest common multiple of 4 and 6 are divisible by 4 and 6. lcm(4, 6) = 12, thus the numbers:
12, 24, 36, 48, 60, 72, 84, 96, 108, 120, 132, 144, 156, 168, 180, 192, 204, 216, 228, 240, 252, 264, 276, 288, 300, 312, 324, 336, 348, 360, 372, 384, 396, 408, 420, 432, 444, 456, 468, 480, 492, 504, 516, 528, 540, 552, 564, 576, 588, 600, 612, 624, 636, 648, 660, 672, 684, 696, 708, 720, 732, 744, 756, 768, 780, 792, 804, 816, 828, 840, 852, 864, 876, 888, 900, 912, 924, 936, 948, 960, 972, 984, 996, 1008, 1020, 1032, 1044, 1056, 1068, 1080, 1092, 1104, 1116, 1128, 1140, 1152, 1164, 1176, 1188, 1200, ...
are divisible by both 4 and 6.
12, 24, 36, 48, 60, 72, 84, 96, 108, 120, 132, 144, 156, 168, 180, 192, 204, 216, 228, 240, 252, 264, 276, 288, 300, 312, 324, 336, 348, 360, 372, 384, 396, 408, 420, 432, 444, 456, 468, 480, 492, 504, 516, 528, 540, 552, 564, 576, 588, 600, 612, 624, 636, 648, 660, 672, 684, 696, 708, 720, 732, 744, 756, 768, 780, 792, 804, 816, 828, 840, 852, 864, 876, 888, 900, 912, 924, 936, 948, 960, 972, 984, 996, 1008, 1020, 1032, 1044, 1056, 1068, 1080, 1092, 1104, 1116, 1128, 1140, 1152, 1164, 1176, 1188, 1200,
Not all even numbers are divisible by 6. These numbers are not evenly divisible by 6: Any number smaller than 6. Any number not divisible by 3. If a number is divisible by both 2 and 3, it is divisible by 6.
No. 189 is only evenly divisible by 3 and 9 (from the set provided). Using the following rules of divisibility on the number 189: Divisible by 2? No - the number is not even Divisible by 3? Yes - the sum of the digits (1 + 8 + 9 = 18) is divisible by 3 Divisible by 4? No - the last two digits are not evenly divisible by 4 Divisible by 5? No - the last digit is not a 0 or a 5 Divisible by 6? No - the number is not even Divisible by 9? Yes - the sum of the digits is divisible by 9 Divisible by 10? No - the number is not divisible by 2 or 5
42, 84
a number is 6. All numbers divisible by both 4 and 15 are the multiples of 4 and 15. Since 4 and 15 have no prime factor in common (4 = 22, 15 = 3 · 5), then the least common multiple of 4 and 15 is equal to their product, namely 4 · 15 = 60. Every other multiple of 4 and 15 is divisible by 60. Thus, if 60 is divisible by a number then all the multiples of 4 and 15 are divisible by that number. Therefore, it is enough to check by which number in the given options is 60 divisible. Only 6 divides 60 and none of the other do. The answer must be (A).
If the last number is divisible by 4 then the whole number is divisable by 4
4- If the last two digits are divisible by 4, the whole number is divisible by 4. 6- If the number is even and also divisible by 3, it is divisible by 6.
There can be no such number. If it is divisible by 5 and 6it must be divisible by 6.
20
18
Any number that ends with 0, 2, 4, 6, or 8 is divisible by 2.Any number that ends with 0, 2, 4, 6, or 8 is divisible by 2.Any number that ends with 0, 2, 4, 6, or 8 is divisible by 2.Any number that ends with 0, 2, 4, 6, or 8 is divisible by 2.
what is the largest three-digit number that is divisible by 4, 5, and 6
Yes.
Yes 1124 is divisible by 4. Since 24 is divisible by 4 1124 is divisible by 4. If the last two numbers of a number are divisible by 4, the number is divisible by 4. 24 divided by 4 is 6.
the least number divisible by 1, 2, 3, 4 & 6 is 12.
There is no number that is divisible by only 6 and 9 because any number is divisible by 1 and itself. Furthermore, any number that is divisible by 6 MUST be divisible by 2 as well as 3 - so only 6 is impossible.
60 is divisible by 3, 4, 5, and 6.
This statement is not always true. While it is true that if a number is divisible by 4, it is also divisible by 2, the reverse is not necessarily true. For example, the number 6 is divisible by 2 but not by 4. In general, being divisible by 2 is a necessary but not a sufficient condition for being divisible by 4.