(60)F: 1, 2, 3, 4, 5, 6, 10, 12, 15, 20, 30
(108)F: 1, 2, 3, 4, 6, 9, 12, 18, 27, 36, 54
(172)F: 1, 2, 4, 43, 86
(136)F: 1, 2, 4, 8, 17, 34, 68
(134)F: 1, 2, 67
(70)F: 1, 2, 5, 7, 10, 14, 35
(74)F: 1,2,37
(40)F: 1, 2, 4, 5, 8, 10, 20
(50)F: 1, 2, 5, 10, 25
(43)F: 1
Terminating.
BRE
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A number with multiples 10 and 5 would not have a factor of 12. A single mystery number would not have a sum of 6. Under these conditions, the mystery number will remain a mystery.
(xy + 7)(x^2y^2 - 7xy + 49)
First you should list all the factors of 60: 1,2,3,4,5,6,10,12,15,20,30 Now we can go through each of the factors and see if we can get another factor to add to 17 with it: For 1 , we would need another factor of 16, which we don't have. Trying 2, we would need 15, which IS a factor. So 2 and 15 would work.
65 has 13 as a factor because 13 divides into 65 evenly with no remainder. The sum of the digits of 65 is 11 because 6 + 5 = 11
They are 15*4 = 60 and 15+4 = 19