(60)F: 1, 2, 3, 4, 5, 6, 10, 12, 15, 20, 30
(108)F: 1, 2, 3, 4, 6, 9, 12, 18, 27, 36, 54
(172)F: 1, 2, 4, 43, 86
(136)F: 1, 2, 4, 8, 17, 34, 68
(134)F: 1, 2, 67
(70)F: 1, 2, 5, 7, 10, 14, 35
(74)F: 1,2,37
(40)F: 1, 2, 4, 5, 8, 10, 20
(50)F: 1, 2, 5, 10, 25
(43)F: 1
Terminating.
BRE
A number with multiples 10 and 5 would not have a factor of 12. A single mystery number would not have a sum of 6. Under these conditions, the mystery number will remain a mystery.
(xy + 7)(x^2y^2 - 7xy + 49)
First you should list all the factors of 60: 1,2,3,4,5,6,10,12,15,20,30 Now we can go through each of the factors and see if we can get another factor to add to 17 with it: For 1 , we would need another factor of 16, which we don't have. Trying 2, we would need 15, which IS a factor. So 2 and 15 would work.
65 has 13 as a factor because 13 divides into 65 evenly with no remainder. The sum of the digits of 65 is 11 because 6 + 5 = 11
They are 15*4 = 60 and 15+4 = 19
A number with multiples 10 and 5 would not have a factor of 12. A single mystery number would not have a sum of 6. Under these conditions, the mystery number will remain a mystery.
12(6 + 5)
Distributive.
No because the digital sum of 143 is 8 and so therefore 9 is not a factor of 143
3 and 2
25 and 18 are a factor pair of 450 whose sum is 43.
A sum that is a factor of 6 has a greater probability.to my dick
.
The smallest prime number that is a factor of the sum of 32009 and 52009 is: 2
#include<stdio.h> #include<conio.h> void factor(int num) { int i,sum=0; for(i=1;i<num;i++) { if(num%i==0) { sum=sum+i; } } printf("Sum of the factor of %d is %d",num,sum); } void main() { int num; printf("Enter the number="); scanf("%d",&num); factor(num); getch(); }
41
69,440