To solve this problem, we can set up the equation n = 7q + 4, where n is the unknown number, q is the quotient, and 4 is the remainder. Since the problem states that when n is divided by 7, the quotient is 3, we can substitute q = 3 into the equation to get n = 7(3) + 4 = 21 + 4 = 25. Therefore, the number in question is 25.
24
Prime factors of 76 are 2.2 and 19 (76=2*2*19). 19 can be divided by 4 with a remainder of 3 (19=4*4+3).
If the number has a remainder of 2 or 4 when divided by 6, it is an even number, so it is not prime number. 6n + 2 = 2 (3n + 1), so it is divisible by 2. 6n + 4 = 2 (3n + 2), so it is divisible by 2. If the number has a remainder of 3 when divided by 6, it is divisible by 3, so it is not a prime number. 6n + 3 = 3 (2n + 1), so it is divisible by 3. However, there are two prime numbers that do not have a remainder of 1 or 5 when divided by 6 : 2 and 3
19
12 is the smallest whole number that gives a remainder of 4 when it is divided by 8.
59
58
29
57
Since the remainder is 0 when the numbers are divided by 3, then that number is a multiples of 3. For example, 45/3 = 15 remainder 0 45/4= 11 remainder 1 45/7 = 6 remainder 3
4
24
179 works until divided by 7 the remainder is 6. 2519 works till 10....
The number is 119. 119/2= 64 R1, 119/3 = 39 R2, 119/4 = 29 R 3, and finally 119/5 = 23 R4. Hope this helps!
solve it with a calculater
The largest 2-digit number is 99. When 99 is divided by 4, the quotient is 24 with a remainder of 3. This is because 99 divided by 4 equals 24 with a remainder of 3.
The answer is 58. 58/5 = 11 +3 58/4 = 14 +2 58/3 = 19 +1