60, 72, 84, 90 and 96 each have twelve factors.
60, 72, 84, 90 and 96. They all have 12 factors
60, 72, 84, 90 and 96. They all have 12 factors
12
Using prime factorization, there are 2 three digit numbers with 9 factors: 512 and 768. There are no three digit numbers with 10 or more prime factors. 512=2^9 and 768=3*2^8
The squares of most 2 digit prime numbers. For example 2809, which is the square of 53, has 3 factors : 1, 53 and 2809 itself.
All numbers have factors. Some factors have one digit. The factors of 24 are 1, 2, 3, 4, 6, 8, 12, 24 The single digit factors of 24 are 1, 2, 3, 4, 6 and 8.
One way to solve this is to multiply the lowest prime numbers together, starting from 2: 2x3=6. 6x5=30. Multiplying by 7 would yield a 3-digit number, so we are looking for all 2-digit numbers with 3 distinct prime factors. We already have 30. 2x3x7=42. 2x3x11=66. 2x3x13=78. 2x5x7=70. So, to answer the original question, the 2-digit numbers that have the most factors in their prime factorization are, in ascending order, 30, 42, 66, 70, and 78.
If you're asking about distinct prime factors, there are eight numbers tied with three of them. If not, 64 has six twos.
Using prime factorization, there are 2 three digit numbers with 9 factors: 512 and 768. There are no three digit numbers with 10 or more prime factors. 512=2^9 and 768=3*2^8
All of them.
36
The squares of most 2 digit prime numbers. For example 2809, which is the square of 53, has 3 factors : 1, 53 and 2809 itself.
Total number of 2-digit numbers = (99 - 9) = 90 of themEvery number that isn't a perfect square has an even number of factors.2-digit numbers that are perfect squares: 16, 25, 36, 49, 64, and 81 = 6 of themRemaining 2-digit numbers = (99 - 6) = 93 .
All numbers have factors. Some factors have one digit. The factors of 24 are 1, 2, 3, 4, 6, 8, 12, 24 The single digit factors of 24 are 1, 2, 3, 4, 6 and 8.
One way to solve this is to multiply the lowest prime numbers together, starting from 2: 2x3=6. 6x5=30. Multiplying by 7 would yield a 3-digit number, so we are looking for all 2-digit numbers with 3 distinct prime factors. We already have 30. 2x3x7=42. 2x3x11=66. 2x3x13=78. 2x5x7=70. So, to answer the original question, the 2-digit numbers that have the most factors in their prime factorization are, in ascending order, 30, 42, 66, 70, and 78.
If you're asking about distinct prime factors, there are eight numbers tied with three of them. If not, 64 has six twos.
Prime factors of 42 are: 2, 3 and 7
12, 16, 24, 32, 48, 96
Two digit numbers are in the range: 10 to 99. Having both 2 & 5 as factors, means the number will be divisible by 10, so there are nine numbers that fit this:{10, 20, 30, 40, 50, 60, 70, 80, 90}
A 3 or 4 digit number.