Well, honey, the 2-digit number that takes the cake for having the most factors is 60. It's like the social butterfly of numbers, with a whopping 12 factors strutting its stuff. So, if you want a number that's popular with all the other numbers, 60 is your go-to.
The 2-digit numbers with the most factors are the highly composite numbers, specifically 60 and 72. These numbers have 12 factors each, as they have a large number of divisors due to their prime factorization. Highly composite numbers are those that have more divisors than any smaller positive integer.
60, 72, 84, 90 and 96. They all have 12 factors
Using prime factorization, there are 2 three digit numbers with 9 factors: 512 and 768. There are no three digit numbers with 10 or more prime factors. 512=2^9 and 768=3*2^8
The squares of most 2 digit prime numbers. For example 2809, which is the square of 53, has 3 factors : 1, 53 and 2809 itself.
One way to solve this is to multiply the lowest prime numbers together, starting from 2: 2x3=6. 6x5=30. Multiplying by 7 would yield a 3-digit number, so we are looking for all 2-digit numbers with 3 distinct prime factors. We already have 30. 2x3x7=42. 2x3x11=66. 2x3x13=78. 2x5x7=70. So, to answer the original question, the 2-digit numbers that have the most factors in their prime factorization are, in ascending order, 30, 42, 66, 70, and 78.
If you're asking about distinct prime factors, there are eight numbers tied with three of them. If not, 64 has six twos.
Well, honey, single digit factors of a number are just the numbers that can divide into that number without leaving a remainder. So, for example, the single digit factors of 12 are 1, 2, 3, 4, and 6. It's like finding out who's invited to the party before you start breaking out the cake.
Using prime factorization, there are 2 three digit numbers with 9 factors: 512 and 768. There are no three digit numbers with 10 or more prime factors. 512=2^9 and 768=3*2^8
36
All of them.
The squares of most 2 digit prime numbers. For example 2809, which is the square of 53, has 3 factors : 1, 53 and 2809 itself.
Total number of 2-digit numbers = (99 - 9) = 90 of themEvery number that isn't a perfect square has an even number of factors.2-digit numbers that are perfect squares: 16, 25, 36, 49, 64, and 81 = 6 of themRemaining 2-digit numbers = (99 - 6) = 93 .
One way to solve this is to multiply the lowest prime numbers together, starting from 2: 2x3=6. 6x5=30. Multiplying by 7 would yield a 3-digit number, so we are looking for all 2-digit numbers with 3 distinct prime factors. We already have 30. 2x3x7=42. 2x3x11=66. 2x3x13=78. 2x5x7=70. So, to answer the original question, the 2-digit numbers that have the most factors in their prime factorization are, in ascending order, 30, 42, 66, 70, and 78.
If you're asking about distinct prime factors, there are eight numbers tied with three of them. If not, 64 has six twos.
Well, honey, single digit factors of a number are just the numbers that can divide into that number without leaving a remainder. So, for example, the single digit factors of 12 are 1, 2, 3, 4, and 6. It's like finding out who's invited to the party before you start breaking out the cake.
Two digit numbers are in the range: 10 to 99. Having both 2 & 5 as factors, means the number will be divisible by 10, so there are nine numbers that fit this:{10, 20, 30, 40, 50, 60, 70, 80, 90}
Prime factors of 42 are: 2, 3 and 7
12, 16, 24, 32, 48, 96
A 3 or 4 digit number.