Since we know the intercepts, its best to solve the general form first and then convert to the standard form.
The intercepts tell us that for some constant, a
y=a*(x+2)(x-6)
We also know that the parabola must run through a given point (1,8) so we can plug that value in to get our value of a
8=a*(3)(-5)
a=-8/15
Next, expand the formula and start moving numbers around until you are in standard form
y=-8/15*(x²-4x-12)
y=-8/15*((x-2)²-16)
y=-8/15*(x-2)²+128/15
It is a continuous line whose shape depends upon what expression it is meant to represent.The equation y = x would be a straight line passing through (0,0) and all the other points where the x and y co-ordinates were equal, including negative ones such as (-11,-11).But if the equation has x squared in it the shape would be a parabola, while the graph of an equation with y cubed in it would have something like an S shape in it. More complex equations could produce many differently shaped lines.
y = (x-4)(x-4) * * * The factors above are shown correctly. The axis of symmetry is the vertical line passing through the vertex, which is the point located at (4, 0). The equation of that line is x = 4, which is the answer you requested.
It would look like a straight vertical line, i.e. parallel to the y-axis, passing through the point on the x-axis where x=3.
Y = 2 The graph is a horizontal line passing through the point Y=2 on the Y=axis. The line is parallel to the X-axis, and exactly 2 units above it everywhere.
18/50
y = 8/49*x2
the equation of a parabola is: y = a(x-h)^2 + k *h and k are the x and y intercepts of the vertex respectively * x and y are the coordinates of a known point the curve passes though * solve for a, then plug that a value back into the equation of the parabola with out the coordinates of the known point so the equation of the curve with the vertex at (0,3) passing through the point (9,0) would be.. 0 = a (9-0)^2 + 3 = 0 = a (81) + 3 = -3/81 = a so the equation for the curve would be y = -(3/81)x^2 + 3
for the equation:5x + 10y = 20, the two intercepts are:x = 0 , y = 2 or (0,2)y = 0 , x = 4 or (4,0)The graph is a straight line passing through the two intercepts (0,2) and (4,0)
The latus rectum of a parabola is a segment with endpoints on the parabola passing through the focus and parallel to the directrix.
A sample equation could be y = 5/3x + 1, the x-intercept is 1 and the y-intercept is -1.
For a straight line equation to be parallel to another straight line equation they both must have the same slopes but different y intercepts.
6666
It is a straight line equation with no x or y intercepts on the Cartesian plane
If you mean of points of (3, -4) and (5, 1) then the equation works out as 2y=5x-23
It does not have a specific name.
What is the equation of the vertical line passing through (-5,-2)
Points: (2, -3) and (-2, 0) Slope: -3/4 Equation: y = -0.75x-1.5