-2x3 + 2x2 + 12x =(-2x) (x2 - x - 6) =(-2x) (x+2) (x-3)
whats the answer for -2x^3+2^2+12x
There is not an answer but you can factor it.3x+3y=3(x+y)
2x^3-3x^2-11x+7x+32x^2-9x+16 R -41x+3 l 2x^3-3x^2-11x+7-(2x^3+6x^2)-9x^2-11x+7-(-9x^2-27x)16x+7-(16x+48)-412x^2-9x+16-[41/(x+3)]
3x + 2y + 5 - 3 = 3x + 2y + 2 No further simplification is possible. This is an expression, not an equation so there cannot be a solution.
2x3 + 8x2 + 3x + 12 = (2x3 + 8x2) + (3x + 12) = 2x2(x + 4) + 3(x + 4) = (x + 4)(2x2 + 3) Since you have asked this question I am assuming that you are not yet at a level where you might want (2x2 + 3) factorised into its imaginary factors.
2x**3-10x**2+3x-15 2x**2(x-5)+3(x-5) (2x**2+3)(x-5)
x=3 so replace x with 3 2(3)+3=2x3+2 =6+2 =8
-2x3 + 2x2 + 12x = -2x(x2 - x - 6) = -2x(x2 + 2x - 3x - 6) = -2x[ x(x + 2) - 3(x + 2) ] = -2x(x - 3)(x + 2)
Rearrange: 4x5 + 6x2 + 6x3 + 9 Group: 2x2 (2x3 + 3) + 3 (2x3 + 3) Simplify to get your answer: (2x2 + 3) (2x3 + 3)
2x^3 - 3x^2 + 4x - 3
-2x3 - 2x2 + 12x = -2x(x2 + x - 6) = -2x(x2 - 2x + 3x - 6) = -2x[ x(x - 2) + 3(x - 2) ] = -2x(x + 3)(x - 2)
Take out the common factor, 3: 3x + 6 = 3(x + 2).
6
(x-2)*(2x2+5x-3) Multiply out the brackets term by term taking care with the minus terms:- 2x3-4x2+5x2-10x-3x+6 Collect like terms:- Answer: 2x3+x2-13x+6
2x4 - 9x3 + 13x2 - 15x + 9 = 2x4 - 6x3 - 3x3 + 9x2 + 4x2 - 12x - 3x + 9 = 2x3(x - 3) - 3x2(x - 3) + 4x(x - 3) - 3(x - 3) = (x - 3)*(2x3 - 3x2 + 4x - 3) So the quotient is (2x3 - 3x2 + 4x - 3) and the remainder is 0.
Six.