If that was 2x^2 + 5x + 2, it would factor to (2x + 1)(x + 2)
2(3x + 4) + 5x - 2
(5x 2 - 8x + 1) + (2x 2 - 4x - 11)
f(x) = 3x2 + 5x + 2fprime(x) = 6x + 5
x2+5x+6 = (x+2)(x+3)
3
5x-1+2= 5x+1
-5x^2 - 55x - 120
5x+2=x+10 5x-x=10-2 4x=8 x=2
x=6Solution:x + 2x + 14 = 5x + 214 - 2 = 5x - 3x12 = 2xx = 12/2 = 6
5x2+ 7x + 2 = (x + 1)(5x + 2).
5x^2 + 20x
Here is the work for that problem: 5x+ 2=12 5x= 12-2 5x=10 x= 2
8x-7 plus 2x equals 6 plus 5x plus 2?
If that was 2x^2 + 5x + 2, it would factor to (2x + 1)(x + 2)
(5x + 2)(x + 3)
2(3x + 4) + 5x - 2