8 + 6y
6*n+25
To calculate 4 times the sum of a number and 6, you would first find the sum of the number and 6, then multiply that sum by 4. Let's represent the number as 'x'. So, the sum of the number and 6 would be x + 6. Multiplying this sum by 4 gives you the expression 4(x + 6), which simplifies to 4x + 24.
The sum of n and the sum of 8 and 6 can be represented as n + (8 + 6). Simplifying the expression within the parentheses first, we get n + 14. Therefore, the final expression representing the sum of n and the sum of 8 and 6 is n + 14.
6+n
Question is about 5x + x + 6 ie 6 (x + 1)
6(4+y)
It can be expressed as: 2x-6
X - 6
(6 * y) +9
The algebraic expression for the sum of 6 times a number and 5 can be written as ( 6x + 5 ), where ( x ) represents the unknown number. This expression indicates that you first multiply the number by 6 and then add 5 to that product.
6(n + y)
6*n+25
To calculate 4 times the sum of a number and 6, you would first find the sum of the number and 6, then multiply that sum by 4. Let's represent the number as 'x'. So, the sum of the number and 6 would be x + 6. Multiplying this sum by 4 gives you the expression 4(x + 6), which simplifies to 4x + 24.
As an algebraic expression it is: 5(x+6) which is equivalent to 5x+30
It could be: 6*(4+659)
the sum of -2 and 6 and 7 is (-2+6+7)
Algebraic expressions are useful for translating problems into the language of mathematics. An algebraic expression for the problem "6 times the sum of 4 and y" would be: 6(4+y) = 24 + 6y.