(x-9)2 + y2 = 484The center is atx = 9y = 0The radius of the circle is 22 .
7x - 9y = 35-3x + 6y = -15 (divide the second equation by 3, after that multiply it by 7)7x - 9y = 35-7x + 14y = -35 (add both equations)5y = 0 (divide both sides by 5)y = 07x - 9y = 35 (substitute 0 for y)7x = 35 (divide both sides by 7)x = 5Thus the solution of the given system of the equations is x = 5 and y = 0.
18
3(x+2) = x -18 3x+6 = x -18 3x -x = -18 -6 2x = -24 x = -12
3x - 9y = 27-9y = -3x + 279y = 3x - 27y = x/3 - 3The graph is a straight line, with (slope = 3), and passing through the point (y = - 3) on the y-axis.
I x=5 and y=2, then (5x5)=25 plus (9x2)=18. 25+18=43
x - 9y = 18At the x-intercept, y=0 :x = 18At the y-intercept, x=0 :-9y = 18-y = 2y = -2
The x-intercept would be 4x + 9(0)= 18 so x = 4.5 (4.5,0) the y-intercept you'd make the x=0. 4(0) + 9y = 18 so y=2 (0,2)
2X + 6Y = 12 3X + 9Y = 18 try elimination - 3(2X + 6Y = 12) 2(3X + 9Y = 18) - 6X - 18Y = - 36 6X + 18Y = 36 ================= I will say this system is dependent and an infinite number of solutions can be found.
x = 2, y = 1
5x-4y+9y+x-9+7 = 5x + x - 4y + 9y - 9 + 7 = 6x + 5y - 2 ■
That is an equation, with an infinite number of solutions. It simplifies to y = 2/3 * x - 2. Two solutions are x = 6, y = 2, and x = 9, y = 4.
9y
3x-2y+9+9y-x = 2x+7y+9
x - 2y=0 so x = 2y 9y - 4x=1 Substituting for x, 9y-4*(2y) = 1 or 9y-8y = 1 so that y = 1 then x = 2y = 2*1 = 2
If that's -18y2, the answer is (3x - 2y)(x + 9y)
We have 3x+9y=36, or equivalently 12x+36y=144. We also have 12x+4y=18, so subtracting these we have 32y=126 or y=63/16. Substituting this into our original equation leaves 3x=36-9*63/16 or x = 12-3*63/16 = 3/16. So: x=3/16, y=63/16