If the graph is a function, no line perpendicular to the X-axis can intersect the graph at more than one point.
f(x) = 0 is a constant function. This particular constant function is both even and odd. Requirements for an even function: f(x) = f(-x) Geometrically, the graph of an even function is symmetric with respect to the y-axis The graph of a constant function is a horizontal line and will be symmetric with respect to the y-axis. y=0 or f(x)=0 is a constant function which is symmetric with respect to the y-axis. Requirements for an odd function: -f(x) = f(-x) Geometrically, it is symmetric about the origin. While the constant function f(x)=0 is symmetric about the origin, constant function such as y=1 is not. and if we look at -f(x)=f(-x) for 1, we have -f(x)=-1 but f(-1)=1 since it is a constant function so y=1 is a constant function but not odd. So f(x)=c is odd if and only iff c=0 f(x)=0 is the only function which is both even and odd.
On the Cartesian plane x is the horizontal axis and y is the vertical axis and they intersect at right angles at the origin (0,0))
The graph of an exponential function f(x) = bx approaches, but does not cross the x-axis. The x-axis is a horizontal asymptote.
If you set a function equal to zero and solve for x, then you are finding where the function crosses the x-axis.
The origin is where x axis and y axis intersect.
It would not touch or intersect the x-axis at all.
Discriminant = 116; Graph crosses the x-axis two times
If the graph is a function, no line perpendicular to the X-axis can intersect the graph at more than one point.
f(x) = 0 is a constant function. This particular constant function is both even and odd. Requirements for an even function: f(x) = f(-x) Geometrically, the graph of an even function is symmetric with respect to the y-axis The graph of a constant function is a horizontal line and will be symmetric with respect to the y-axis. y=0 or f(x)=0 is a constant function which is symmetric with respect to the y-axis. Requirements for an odd function: -f(x) = f(-x) Geometrically, it is symmetric about the origin. While the constant function f(x)=0 is symmetric about the origin, constant function such as y=1 is not. and if we look at -f(x)=f(-x) for 1, we have -f(x)=-1 but f(-1)=1 since it is a constant function so y=1 is a constant function but not odd. So f(x)=c is odd if and only iff c=0 f(x)=0 is the only function which is both even and odd.
Yes
No
The origin.
(0,0) that is the point where the x axis and y axis intersects at Known as the "origin".
If a point is on both the x-axis and the y-axis, then it must be in the only point where the x-axis and y-axis intersect. The point where they intersect is (0,0) which is called the origin.
No real roots. Imaginary roots as this function does not intersect the X axis.
When y = 0