x^2 + x = 110.
x(x + 1) equals x squared + x.
Let the two consecutive positive integers be ( n ) and ( n + 1 ). Their product can be expressed as ( n(n + 1) = 600 ). This simplifies to the quadratic equation ( n^2 + n - 600 = 0 ). Solving this using the quadratic formula, we find that ( n = 24 ) and ( n + 1 = 25 ), so the two consecutive integers are 24 and 25.
It can be.
12 and 14.
The 3 consecutive odd positive integers are 7, 9 and 11.
There are an infinite number of positive integers that satisfy the equation x^4 + y < 70.
For x, which is the largest integer of nconsecutive positive integers of which the smallest is m:x = m + n - 1
The sum of the squares of two consecutive positive even integers is 340. Find the integers.
The set of positive integers, of course!
There are two consecutive odd integers whose sum is 340. They are 169 and 171.
Let the two consecutive positive integers be ( n ) and ( n + 1 ). Their product can be expressed as ( n(n + 1) = 600 ). This simplifies to the quadratic equation ( n^2 + n - 600 = 0 ). Solving this using the quadratic formula, we find that ( n = 24 ) and ( n + 1 = 25 ), so the two consecutive integers are 24 and 25.
There are no two consecutive integers, negative or positive, whose product is 440.
i dont now
The numbers are 65 and 67.
It can be.
8 & 9
112+92 is 202.
12 and 14.