(x + 4)(y - 2)
(x + 4)(y - 2)
xy-2x+4y-8 x(y-2)+4(y-2) (x+4)(y-2)
(y-2) (x+4)
xy(3x - 2y)(2x + 3y)
xy plus 2x plus 4y plus 8 or (xy+2x) + (4y+8) or x(y+2) + 4(y+2) or (x+4)(y+2)
(x + 4)(y - 2)
(x + 4)(y - 2)
xy-2x+4y-8 x(y-2)+4(y-2) (x+4)(y-2)
(y-2) (x+4)
( 2xy - 4x ) + ( 8y - 16)2 ( xy - 2x ) + 2 ( 4y - 8 ) Answer
(x - 1)(2x + y)
4
Divide by 'x'; x2+xy/x = x(x+y)
xy(3x - 2y)(2x + 3y)
If this is a question about factorisation check the signs. As it stands, it cannot be factorised.
In order to combine terms, the variable(s) must be the same and the exponent(s) must be the same on the variables. Since you have an x2 term, x term, xy term and y term, none of the terms can be combined. So, the answer is: x2 + 4x + xy + 4y. The only thing you could do in this problem is to factor out a 4 from the 4x & 4y so another way to write this is: x2 + xy + 4(x + y).