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Since the 2 would be the x in the center coordinate (x,y) and 8 would be the y respectively they would fit into the following equation for a circle as follows: (x-h)^2 + (y-k)^2 = r^2 (x-2)^2 + (y-8)^2 = (square root of 10)^2 Remember that the 2 for the x would become negative because the equation states that the h value becomes negative....same for the y value as well. The final equation after squaring the square root of 10 would be: (x-2)^2 + (y-8)^2 = 10 This would be the final equation of the circle with center (2,8) and radius of root 10. Hope this helped! :) I'd guess that your question involves a circle centered at the cartesian coordinate (2,8): Your standard equation goes as follows: (x-2)2+(y-2)2=10 x2+y2-4x-16y+58=0 for circle with centre at(2,8) and radius the squareroot of 10. (x-2)^2 + (y-8)^2 = 10
Assuming that 1inch is your diameter, your radius is, of course, 0.5. Since the area of a circle is expressed asA=(pi)r2simply plug in the radius to this equation. You will get your area to be pi*0.25in2, which is roughly equal to 0.78539inches2.
not cool
there is no problem with this quadratic equation it's 2x square - 3x -2 = 0 I need an answer. where it says square there should be a little 2 at the top corner of the 2x to make it 2x square thanks If you can't factor it easily then use the quadratic equation: The two solutions are: 2 & -.5
Divide the area by pi then square root your answer which will give the radius of the circle and use 2*pi*radius to find the circumference.
113.09734 square inches
The radius of a circle with an area equal to 225.97 square inches is: 8.481 inches.
It is the equation of a circle with radius of 6 and its center at the origin.
Approx 6.6 cm.
If you multiply an egg by an egg, you get a square egg. This is similar to the equation circle x circle = square circle
Every mixed number is more than ' 1 '. If the radius of the circle is more than '1', then the area of the circle is more than (pi) square units.
Assuming the circle is tangent to the sides of the square, then the edges of the circle meet the square at the midpoint on each of the four sides. So the diameter of the circle is the same as the length of a side of the square. So all you need to do is find the length from the total area by taking the square root of the area (since A = s2), which gives you the diameter, then halve it to get the radius.
Divide the area by pi. (3.14 or 22/7) Find the square root of your answer. This will be the radius. Multiply the raduis by 2.
If ... the square of (the x-coordinate of the point minus the x-coordinate of the center of the circle) added to the square of (the y-coordinate of the point minus the y-coordinate of the center of the circle) is equal to the square of the circle's radius, then the point is on the circle.
You are describing a circle, with its center at the origin and a radius of 4 (the square root of 16)
A circle with radius 15mm will fit in a 30mm square. Find the intersection of the square's diagonals, that is the center of the circle.
End points: (8, 7) and (2, -3) Midpoint: (5, 2) which is the center of the circle Radius: square root of 34 Equation of the circle: (x-5)^2 +(y-2)^2 = 34