the answer is (3x-2)(9x squared+6x+4)
Answer : 12
the derivative of 3x is 3 the derivative of x cubed is 3 times x squared
Your answer will depend on the parameters of the instructions. If you're looking for the first derivative, simply use the product rule by changing the denominator to a negative exponent and bringing it up (take the negative square root of the quantity x-2 to the top). Then, follow the rules of calculus and algebra. Wow, that's a mess. Let's see... you get "the quantity x cubed plus 6x squared plus 3x plus 1 times the quantity -1(x-2) raised to the negative second plus the quantity x-2 raised to the negative first times the quantity 3x squared plus 12x plus 3." This is because of the Product Rule. Simplifying (by factoring out (x-2) raised to the negative second and combining like terms) gives us "(x-2) raised to the negative second times the quantity 2x cubed minus 24x minus 7." This can also be written as "2x cubed minus 24x minus 7 all over the quantity x-2 squared." f'(x)= 2x^3-24x-7 (x-2)^2
9x2 - 6xy + y2 - 81 = (3x - y)2 - 81 = (3x - y - 9)*(3x - y + 9)
x3+3x2+3x+2 divided by x+2 equals x2+x+1
x3+3x2+6x+1 divided by x+1 Quotient: x2+2x+4 Remaider: -3
3x3+15x2+18x = 3x(x2+5x+6) = 3x(x+2)(x+3)
4x(4x^2 + 3x + 1)
the answer is (3x-2)(9x squared+6x+4)
24
(x + 2)(3x - 1)(3x + 1)
The 3x is cubed and the 4x is squared
x^2 + 3x + 2/(-3x) - x^2 - 2=3x-2+2/(-3x)=3x-2-2/(3x)
(8x + 9)(3x^2 - 1)
9x2 + 3x / 3x equals (3x + 1).9x2 + 3x divided by x is 9x + 3 , and then divided by 3 yields the 3x +1.
Factorise it: (x + 5)(3x - 8)