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f(x)= sin(1/x) and g(x)=1/sin(x)

[u(v)]' = u'(v) * v', where u and v are functions

So

f'(x) = sin'(1/x) * (1/x)' = cos(x) * (-1/x2) = -cos(x)/x2

g'(x) = (1/x)' applied to sin(x) * (sin(x))' = -1/(sin2(x)) * cos(x) = -cos(x)/(sin2(x))

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12y ago
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