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The period is the length of x over which the equation repeats itself. In this case, y=sin x delivers y=0 at x=0 at a gradient of 1. y next equals 0 when x equals pi, but at this point the gradient is minus 1. y next equals 0 when x equals 2pi, and at this point the gradient is 1 again. Therefore the period of y=sinx is 2pi.
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Find the amplitude and period of the functions and sketch their graphs y equals sin -x?
y = sin(-x)Amplitude = 1Period = 2 pi
What is the period of y equals sin5x?
The period of y=sin(x) is 2*pi, so sin(x) repeats every 2*pi units. sin(5x) repeats every 2*pi/5 units. In general, the period of y=sin(n*x) is 2*pi/n.
If Sin equals x and Cos equals y then x squared equals what function of y?
If x = sin θ and y = cos θ then: sin² θ + cos² θ = 1 → x² + y² = 1 → x² = 1 - y²
How do you rewrite y equals cscx to graph it?
You could try y = 1/sin(x) but I do not see how that helps.
What is the domain of the function y sin x?
y= sin 3x
What is the period of y equals 2sinx?
The same as the period of y = sin x. This period is equal to (2 x pi).
What is the period of y equals 3 sin pi x?
2
Find the amplitude and period of the functions and sketch their graphs y equals sin -x?
y = sin(-x)Amplitude = 1Period = 2 pi
Determine the period of y equals -3 sin x?
the period is 2pi. period is 2pi/b and the formula is y=AsinBx.
What is the period of y equals sin5x?
The period of y=sin(x) is 2*pi, so sin(x) repeats every 2*pi units. sin(5x) repeats every 2*pi/5 units. In general, the period of y=sin(n*x) is 2*pi/n.
If Sin equals x and Cos equals y then x squared equals what function of y?
If x = sin θ and y = cos θ then: sin² θ + cos² θ = 1 → x² + y² = 1 → x² = 1 - y²
What is the period for y-3 sin x?
y = 3 sin x The period of this function is 2 pi.
The function y equals sin θ is not a function beacause sin 30 equals sin 150?
Y=sin X is a function because for each value of X, there is exactly one Y value.
Y equals 4 sin x for x equals pi?
sin(pi) = 0 so 4*sin(pi) = 0 so Y = 0
What is the range of y equals sin2x?
range of y=sin(2x) is [-1;1] and in generally when is y=sin(k*x) (k=....-1,0,1....) range is always [-1;1] and the period is w=(2pi)/k
Determine the amplitude of y equals -2 sin x?
The amplitude of the wave [ y = -2 sin(x) ] is 2.
What is the derivative of y equals sin times x to the power of 2?
D(y)= sin 2x
