The period is the length of x over which the equation repeats itself. In this case, y=sin x delivers y=0 at x=0 at a gradient of 1. y next equals 0 when x equals pi, but at this point the gradient is minus 1. y next equals 0 when x equals 2pi, and at this point the gradient is 1 again. Therefore the period of y=sinx is 2pi.
y = sin(-x)Amplitude = 1Period = 2 pi
The period of y=sin(x) is 2*pi, so sin(x) repeats every 2*pi units. sin(5x) repeats every 2*pi/5 units. In general, the period of y=sin(n*x) is 2*pi/n.
If x = sin θ and y = cos θ then: sin² θ + cos² θ = 1 → x² + y² = 1 → x² = 1 - y²
You could try y = 1/sin(x) but I do not see how that helps.
y= sin 3x
The same as the period of y = sin x. This period is equal to (2 x pi).
2
y = sin(-x)Amplitude = 1Period = 2 pi
the period is 2pi. period is 2pi/b and the formula is y=AsinBx.
The period of y=sin(x) is 2*pi, so sin(x) repeats every 2*pi units. sin(5x) repeats every 2*pi/5 units. In general, the period of y=sin(n*x) is 2*pi/n.
If x = sin θ and y = cos θ then: sin² θ + cos² θ = 1 → x² + y² = 1 → x² = 1 - y²
y = 3 sin x The period of this function is 2 pi.
Y=sin X is a function because for each value of X, there is exactly one Y value.
sin(pi) = 0 so 4*sin(pi) = 0 so Y = 0
range of y=sin(2x) is [-1;1] and in generally when is y=sin(k*x) (k=....-1,0,1....) range is always [-1;1] and the period is w=(2pi)/k
The amplitude of the wave [ y = -2 sin(x) ] is 2.
D(y)= sin 2x