Yes. y = x6 has only one solution, at (0, 0).
In fact, if you think about it, the family of equations y = a(x+b)6 (where a and b can be any real constant; including x6, 2(x-4)6, 42(x+1)6, and so on) all have one solution. Other than these equations, however, sixth-degree polynomials almost always have multiple solutions or none at all.
Easy. Same thing as the graph of f(x) = x^2 + 1 which have NO intercept.
If the equations or inequalities have the same slope, they have no solution or infinite solutions. If the equations/inequalities have different slopes, the system has only one solution.
when the variable is to the power one you will only have one answer....2 solutions when to the power 23 when cubed etc.note: when multiple answers it is possible for answers to repeat ex. x^2+4x+4 =0would factor to (x+2)(x+2)=0 so x=-2 and x=-2 there is only one answer but it repeats. [Note: the graph of this parabola will 'just touch' the x-axis at x = -2]Also, it may seem that there is only one solution, for example x³ - 5x² + 8x - 6 = 0 looks like it only has one solution at x = 3 (as the graph of it will only cross the x-axis once at x = 3), but there are two more solutions which require the use of complex numbers, in this case namely x = 1 + i, and x = 1 - i (where i = √-1).
-9x = 27 x = -3 The solution set contains only one value for x, -3, which is just a point on the number line 3 units to the left of zero.
The system of equations can have zero solutions, one solution, two solutions, any finite number of solutions, or an infinite number of solutions. If it is a system of LINEAR equations, then the only possibilities are zero solutions, one solution, and an infinite number of solutions. With linear equations, think of each equation describing a straight line. The solution to the system of equations will be where these lines intersect (a point). If they do not intersect at all (or maybe two of the lines intersect, and the third one doesn't) then there is no solution. If the equations describe the same line, then there will be infinite solutions (every point on the line satisfies both equations). If the system of equations came from a real world problem (like solving for currents or voltages in different parts of a circuit) then there should be a solution, if the equations were chosen properly.
You forgot to copy the polynomial. However, the Fundamental Theorem of Algebra states that every polynomial has at least one root, if complex roots are allowed. If a polynomial has only real coefficients, and it it of odd degree, it will also have at least one real solution.
There are infinitely many possible answers. The only solution in the form a cubic polynomial is Un = (25n3 - 147n2 + 236n - 120)/12 for n = 1, 2, 3, 4
5
No, the correct capitalization is: "Only one solution is possible: you must cut your expenses."
No, there can be many solutes in a solution, but only one solvent.
No. A polynomial can have as many degrees as you like.
A polynomial discriminant is defined in terms of the difference in the roots of the polynomial equation. Since a binomial has only one root, there is nothing to take its difference from and so in such a situation, the discriminant is a meaningless concept.
It is not possible to say.
NP stands for Nondeterministic Polynomial time, and is a class of complexity of problems. A problem is in NP if the computing time needed grows exponentially with the amount of input, but it only takes polynomial time to determine if a given solution is correct or not.It is called nondeterministic because a computer that always automatically chooses the right course of action in each step would come up with a correct solution in polynomial time.
zero polynomial which is 0 and only 0 = 0.
It is not possible to give a sensible answer to this question. The greatest common factor (GCF) refers to a factor that is COMMON to two or more numbers or polynomials. If you have only one number or polynomial there is nothing for it to have a factor in common with!
No. By the definition of a polynomial, the powers can only be non-negative integers.