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Yes. y = x6 has only one solution, at (0, 0).

In fact, if you think about it, the family of equations y = a(x+b)6 (where a and b can be any real constant; including x6, 2(x-4)6, 42(x+1)6, and so on) all have one solution. Other than these equations, however, sixth-degree polynomials almost always have multiple solutions or none at all.

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Q: Is it possible for a sixth-degree polynomial to have only one solution?
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The system of equations can have zero solutions, one solution, two solutions, any finite number of solutions, or an infinite number of solutions. If it is a system of LINEAR equations, then the only possibilities are zero solutions, one solution, and an infinite number of solutions. With linear equations, think of each equation describing a straight line. The solution to the system of equations will be where these lines intersect (a point). If they do not intersect at all (or maybe two of the lines intersect, and the third one doesn't) then there is no solution. If the equations describe the same line, then there will be infinite solutions (every point on the line satisfies both equations). If the system of equations came from a real world problem (like solving for currents or voltages in different parts of a circuit) then there should be a solution, if the equations were chosen properly.

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No, the correct capitalization is: "Only one solution is possible: you must cut your expenses."


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