sin2 + cos2 = 1
So, (1 - 2*cos2)/(sin*cos) = (sin2 + cos2 - 2*cos2)/(sin*cos)
= (sin2 - cos2)/(sin*cos)
= sin2/(sin*cos) - cos2/(sin*cos)
= sin/cos - cos-sin
= tan - cot
No, it is not. To be correct, the expression requires parenthesis, which are missing.
No, it does not.
Cosine squared theta = 1 + Sine squared theta
No, they do not.
pineapple
You could just pull out the half: it will be (1/2) cos squared x.
Since you didn't specify which trigonometric function you're using, I'll give you all of them.120 in Degreessin120 ~ 0.87cos120 ~ -0.5tan120 ~ -1.73csc120 ~ 1.15sec120 = -2cot120 ~ -0.58Answer in Degreesarctan120 ~ 89.52arccot120 ~ 0.48120 in Radianssin120 ~ 0.58cos120 ~ 0.81tan120 ~ 0.71csc120 ~ 1.72sec120 ~ 1.23cot120 ~ 1.4Answer in Radiansarctan120 ~ 1.56arccot120 ~ 0.008
The tangent of an angle theta is defined as sine(theta) divided by cosine(theta). Since the sine and cosine are Y and X on the unit circle, then tangent(theta) is Y divided by X. The tangent of a function at a point is the line going through that point which has slope equal to the first deriviative of the function at that point.
2 x cosine squared x -1 which also equals cos (2x)
The ratio is called the tangent of the angle. (also equal to sine/cosine)
The tangent function is equal to the sine divided by the cosine. In quadrant III, both sin and cos are negative - and a negative divided by another negative is positive. Thus it follows that the tangent is positive in QIII.
Cotangent of ∞ is not π/2. It's actually nonexistent since cotangent is the continually oscillating function.