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How do I write an equation in standard form for a line satisfying the given condition. Through -2 and 9 and -2 and 7.?
In general, if a line passes through the points (a, b) and (c, d), its equation can be written as:
y - b = [(d - b)/(a - c)](x - a)
In this case, however, the formula is not necessary -- and in fact, attempting to apply it in its current form would result in a division by zero error. Instead, however, we can simply note that from (-2, 9) to (-2, 7) the x-coordinate does not change. This can only be the case if the line is vertical, meaning that the x-coordinate never changes. The line can therefore be represented by the equation x = -2.
What else can I help you with?
What is the solution to the equation y equals -2.5?
The equation y = -2.5 represents a horizontal line on the Cartesian plane passing through the point (-2.5, 0). This line is parallel to the x-axis and has a slope of 0. The solution to this equation is all real numbers on the y-axis that have a value of -2.5.
What is the graph of the equation -5x plus 2y equals 2?
A straight line through the points (0, 1) and (-0.4, 0).
How do you know the relationship between x and y is proportional?
The answer depends on how the information is presented. If in the form of a graph, it must be a straight line through the origin. If in the form of an equation, it must be of the form y = cx.
How do you find the equation of a parabola in standard form with x intercepts at -2 and 6 passing through 1 and 8?
Since we know the intercepts, its best to solve the general form first and then convert to the standard form. The intercepts tell us that for some constant, a y=a*(x+2)(x-6) We also know that the parabola must run through a given point (1,8) so we can plug that value in to get our value of a 8=a*(3)(-5) a=-8/15 Next, expand the formula and start moving numbers around until you are in standard form y=-8/15*(x²-4x-12) y=-8/15*((x-2)²-16) y=-8/15*(x-2)²+128/15
What is the equation of the axis of symmetry y equals x2 - 8x plus 16?
y = (x-4)(x-4) * * * The factors above are shown correctly. The axis of symmetry is the vertical line passing through the vertex, which is the point located at (4, 0). The equation of that line is x = 4, which is the answer you requested.
Write an equation in standard form of the line satisfying the following condition the line through -55 and is horizonal?
I need step by step on my graphic calculator on how to write an equation
Write an equation in standard form for a line satisfying the given condition Through -2 and 9 and -2 and 7?
that's a verticle line cuz the x stays the same so it is X=-2
4. Write an equation in standard form for a line satisfying the given condition. Through -2 and 9 and -2 and 7.?
The standard form is Ax + By = C. The slope of the line is (9-7)/(-2 - (-2)) or 2/0. This indicates that this is a vertical line whose x intercept is -2. The equation of the line is then x = -2.
Can you write an equation in standard form for a line satisfying the given conditions through the point 0 and 4 with a slope of 5?
The standard form is: 5x - y + 4 = 0
What is the equation of the line that passes through (05) and has a slope of 2?
The standard form of the equation is 2x - y + 5 = 0
Write an equation in standard form of the line through ordered pairs?
(3,1)(3,2)
Find an equation in standard form for the passing through the points 1 4 and -3 4?
6666
Can you write an equation in standard form for a line satisfying the given conditions through the point 0 and 4 with a slope of -4.5?
You use slope intercept (y=mx+b) to find yourb(y-intercept) 4=-4.5(0) + b 4=b therfore y=-4.5x + 4. Then you change it into standard form (Ax + By = C) y= -4.5x +4 4.5x + y =4 is your answer.
What is the standard for equation of the line passing through the points (3-4) and (51)?
If you mean of points of (3, -4) and (5, 1) then the equation works out as 2y=5x-23
Which is an equation of a line with a slope of 2 and goes through the points of (03)?
If you mean a point of (0, 3) and a slope of 2 then the equation is y = 2x+3
What is an equation of a line through (-5 1) with a slope of 7 standard form?
To find the equation of a line in standard form (Ax + By = C) that passes through the point (-5, 1) with a slope of 7, we can use the point-slope form first: (y - 1 = 7(x + 5)). Simplifying this gives (y - 1 = 7x + 35) or (y = 7x + 36). Rearranging to standard form results in (-7x + y = 36) or (7x - y = -36). Thus, the standard form of the equation is (7x - y = -36).
What is the standard form of the equation of the line through 6 -3 with slope 2 over 3?
Y=2/3x - 7
