y = (x-4)(x-4)
* * *
The factors above are shown correctly.
The axis of symmetry is the vertical line passing through the vertex, which is the point located at (4, 0).
The equation of that line is x = 4, which is the answer you requested.
y = 2x2 + 3x + 6 Since a > 0 (a = 2, b = 3, c = 6) the graph opens upward. The coordinates of the vertex are (-b/2a, f(-b/2a)) = (- 0.75, 4.875). The equation of the axis of symmetry is x = -0.75.
By completing the square y = (x+3)2+1 Axis of symmetry and vertex: x = -3 and (-3, 1) Note that the parabola has no x intercepts because the discriminant is less than zero
It's a linear equation in two variables. When it's graphed, the graph is a straight line with a slope of 12 that intersects the y-axis at y=120.
(3/4, 0) and (5/2, 0) Solved with the help of the quadratic equation formula.
no
Line of symmetry: x = 3
y = 2x + 2 + 4x+ 2 = 6x + 4 This is NOT a symmetric function and so there is no axis of symmetry.
-1
y = x2 + 8x - 7 a = 1, b = 8, c = -7 the equation of the axis of symmetry: x = -b/2a x = -8/(2*1) = -4
y=x2+2x+1 -b -2 2a= 2= -1 = axis of symmetry is negative one.
y = 2x2 + 3x + 6 Since a > 0 (a = 2, b = 3, c = 6) the graph opens upward. The coordinates of the vertex are (-b/2a, f(-b/2a)) = (- 0.75, 4.875). The equation of the axis of symmetry is x = -0.75.
When x = -5
The second
It is a straight line equation with a slope of 14 and a y intercept of -5
At: x = 6
In the form y = ax² + bx + c the axis of symmetry is given by the line x = -b/2a The axis of symmetry runs through the vertex, and the vertex is given by (-b/2a, -b²/4a + c). For y = 2x² + 4x - 10: → axis of symmetry is x = -4/(2×2) = -4/4 = -1 → vertex = (-1, -4²/(4×2) - 10) = (-1, -16/8 - 10) = (-1, -12)
-1.83 . . . . . and . . . . . -1.82