Oh, dude, it's like super easy. So, to differentiate 2tanx, you just use the chain rule. You take the derivative of tanx, which is sec^2x, and then multiply it by the derivative of the inside function, which is just 2. So, the answer is 2sec^2x. Easy peasy, right?
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To differentiate 2tanx, you can use the chain rule of differentiation. The derivative of tanx is sec^2x, so the derivative of 2tanx would be 2 times the derivative of tanx, which is 2sec^2x. Therefore, the derivative of 2tanx is 2sec^2x.
Coefficients can be removed when differentiating, i.e. d/dx 2tanx = 2 d/dx tanx
You should know that d/dx tanx = sec2x (either by differentiating sinx/cosx or by just remembering the derivatives of common trig functions, as it will come in handy).
So the answer is 2sec2x
For a number in form af(x) while differentiating with dont interfere with the constant a.
So, it is a d(f(x))/dx
Here assuming were differentiating with respect to x,
we have 2*d(tan x)/dx
From here you have options weather you can differentiate ie based on uv or u/v method. I'll be using u/v (easy to apply for division),
Here's the general form,
(u/v)' = {vu' - uv'}/v^2
d(tan x)/dx =d(sinx/cosx )/dx = {cosx(sinx)' - sinx(cosx)'}/(cos^2)
= {(cos^2 x) - (-sin^2x)}/cos^2 = {(cos^2 x) +(sin^2x)}/cos^2
Since sin^2 x + cos^2 x =1 ,
we have
d(tan x)/dx = 1/cos^2x = sec ^2 x.
Therefore the final answer for,
2d(tan x)/dx = 2sec^2 x
Well, honey, differentiating 2tanx is as easy as pie. Just use the chain rule and remember that the derivative of tanx is sec^2x. So, the derivative of 2tanx is simply 2sec^2x. Voila!
dy/dx = 3 integral = (3x^2)/2
y = Sin(x) dy/dx = Cos(x)
log 3 is a constant, so d/dx log3, like d/dx of any constant, equals zero.
The open channel flow has a free surface whereas the pipe flow has a closed surface.
The derivative of the ln function is the function 1/x. So the derivative of ln1.01 should be 1/1.01 = 0.990099... ------------------------- Well I may be looking at this slightly different, but the question as stated "differentiate ln(1.01)" would be 0 seeing as ln(1.01) is itself a constant (irrational) number. The derivative of any constant is zero. If the intended question was ln(x)d/dx where x=1.01 then I agree with the above answer.