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sec4(Θ) - sec2(Θ) = tan4(Θ) + tan2(Θ)

Factor each side: sec2(Θ) [sec2(Θ) - 1] = tan2(Θ) [tan2(Θ) + 1]

Use the identitiy: 1 + tan2(Θ) = sec2(Θ)

We can also write it as: tan2(Θ) = sec2(Θ) - 1

Substitute the first form of the identity in the right side: sec2(Θ) [sec2(Θ) - 1] = tan2(Θ) sec2(Θ)

Substitute the second form of the identity in the left side: sec2(Θ) tan2(Θ) = tan2(Θ) sec2(Θ)

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Q: Can someone verify that sec4 theta-sec2 theta equals tan4 theta plus tan2 theta?
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