y = x/2 + 1
This is a line of the form y = mx + c
When c = 1 it passes through the y-axis at y = 1
When m= 1/2 ( 0.5) it has a gradient of 1/2 )0.5) . For every two places along in 'x', you go up one place in 'y'.
So to plot two point
s
When x = 1 ; y = 1/2 + 1 = 3/2 ( 1,3/2)
When x - 2 ; y = 2/2 + 1 =. 1 + ` = 2 (2,2)
et seq.,
A graph that has 1 parabolla that has a minimum and 1 positive line.
answer is 1
A straight line through the points (0, 1) and (-0.4, 0).
y = x2 + 2x + 1zeros are:0 = x2 + 2x + 10 = (x + 1)(x + 1)0 = (x + 1)2x = -1So that the graph of the function y = x + 2x + 1 touches the x-axis at x = -1.
3
y=x+1 there for answer is 2
-2x plus 3y equals 1
A graph that has 1 parabolla that has a minimum and 1 positive line.
3
answer is 1
The lines are parallel.
5x2 - x - 4 = 0(5x + 4) (x - 1) = 05x + 4 = 05x = -4 ===> x = -(4/5)x - 1 = 0 ==> x = 1
Same way you graph y = -4x - 0.5
(-1,0)
1
+ 1/8
y=-10x-4