x2-1=(x-1)(x+1)
It factors out like this because it's the difference of two squares. It only works with subtraction and is always in the format with two groups of parenthases. For example: 16x-4. 16 and 4 are both squares, so it factors out like this: (4x+2)(4x-2). One set is always minus, the other is always plus. The order doesn't matter.
Nope! It's (x+ 1) (x-1). :)
x^2(1 - x)(1 + x)
2(x - 7)(x - 1)
(x + 2)(x - 4)
The answer to this depends on what you mean by "x 7" If you mean: x2 -7x, then it can be factored out as x(x - 7) If you mean: x2 - x7, then you can factor it out as: x2(1 - x5) If you mean: x2 - x + 7, then it can not be factored If you mean: (x2 - x)7, then the inner term can be factored, giving you (x[x - 1])7 If you mean something else, then you will need to be more clear with your question.
What about it? Factorise it?
x(x - 7)
13X squared + 7X + 12
X2 - 4= (x + 2)(x - 2)===========
5x2 + 9x + 13 has no real factors.
( x2 - 121 ) = (x + 11) times (x - 11)
3x2 - 8x = x(3x - 8)
(x - 3)(2x - 7)
(x + 2)(x + 1)
Factorise it: (x + 5)(3x - 8)
It is (x+5)(x+1) when factored
X squared + 7X + 12?