Algebraically. X = integer.
X + (X + 1) + (X + 2) = - 123
3X + 3 = - 123
3X = - 126
X = - 42
X + 1 = - 41
X + 2 = - 40
- 42 + - 42 + - 40
= -123
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The sum is 3*(x-1) or 3x - 3
72/3 = 24 and 7+8+9 = 24 so the integers are 7, 8 and 9.
1+8+0 = 9 or 180+80+0 = 260
-4, -2, 0, and 2 are the four consecutive even integers. When you add them up they equal -4.
Let's see if this is true. Assume that their sum is 48. So, x + (x +1) + (x + 2) = 48 3x + 3 = 48 Subtract 3 at both sides; 3x = 45 Divide 3 to both sides; x = 15 x + 1 = 15 + 1 = 16 x + 2 = 15 + 2 = 17 So, 15 + 16 + 17 = 48 Answer: The sum of three consecutive integers such as 15, 16, and 17 is 48.