They are 35.1 and 324.9 degrees.
cos(theta) = 0.7902 arcos(0.7902) = theta = 38 degrees you find complimentary angles
The answer is 60 and 240 degrees. Add radical 3 and inverse tan to get answer add 180 for other answer less than 360.
The general solution to a trigonometric equation provides all possible angles that satisfy the equation. For example, for equations involving sine or cosine, the general solutions can often be expressed in the form ( x = n \cdot 2\pi + \theta ) or ( x = n \cdot 2\pi - \theta ) for sine, or ( x = n \cdot 2\pi + \theta ) for cosine, where ( n ) is any integer and ( \theta ) is a specific angle solution. This reflects the periodic nature of trigonometric functions, allowing for infinitely many solutions based on the periodic intervals.
The equation to calculate work is given by ( W = F \cdot d \cdot \cos(\theta) ), where ( W ) is the work done, ( F ) is the force applied, ( d ) is the distance over which the force is applied, and ( \theta ) is the angle between the force and the direction of motion. Work is measured in joules (J) in the International System of Units (SI). If the force is applied in the same direction as the motion, ( \theta ) is 0 degrees, and the equation simplifies to ( W = F \cdot d ).
In the work equation, the angle used is the angle between the direction of the force applied and the direction of displacement. The work done (W) is calculated using the formula ( W = F \cdot d \cdot \cos(\theta) ), where ( F ) is the magnitude of the force, ( d ) is the displacement, and ( \theta ) is the angle. If the force is in the same direction as the displacement, ( \theta ) is 0 degrees, and the work done is maximized. If the force is perpendicular to the displacement, the work done is zero.
They are theta = -34.99 degrees and 145.09 deg.
It is a simple trigonometric equation. However, without information on whether the angles are measures in degrees or radians, and with no domain for theta, the equation cannot be solved.
108.435 degrees 288.435 degrees (decimal is rounded)
96 degrees Let theta represent the measure of the angle we are trying to find and theta' represent the measure of its supplement. From the problem, we know: theta=theta'+12 Because supplementary angles sum to 180 degrees, we also know: theta+theta'=180 Substituting the value from theta in the first equation into the second, we get: (theta'+12)+theta'=180 2*theta'+12=180 2*theta'=180-12=168 theta'=168/2=84 Substituting this value for theta' back into the first equation, we get: theta+84=180 theta=180-84=96
cos(theta) = 0.7902 arcos(0.7902) = theta = 38 degrees you find complimentary angles
In the context of the keyword "asin theta m lambda," the relationship between the angle theta, the mass m, and the wavelength lambda is described by the equation asin(theta) m lambda. This equation relates the sine of the angle theta to the product of the mass m and the wavelength lambda.
The answer is 60 and 240 degrees. Add radical 3 and inverse tan to get answer add 180 for other answer less than 360.
The general solution to a trigonometric equation provides all possible angles that satisfy the equation. For example, for equations involving sine or cosine, the general solutions can often be expressed in the form ( x = n \cdot 2\pi + \theta ) or ( x = n \cdot 2\pi - \theta ) for sine, or ( x = n \cdot 2\pi + \theta ) for cosine, where ( n ) is any integer and ( \theta ) is a specific angle solution. This reflects the periodic nature of trigonometric functions, allowing for infinitely many solutions based on the periodic intervals.
x = r*cos(theta) y = r*sin(theta) for alpha < theta < alpha + 90 degrees where r is the radius and alpha is any angle (which determines the direction in which the quarter circle is facing).
answer is 2.34 degrees answer is 2.34 degrees
Sin theta of 30 degrees is1/2
Sin(theta) = 0.03125 Hence theta = ArcSin(0.03125) theta = 1.790784659... degrees.