0
Cos(360 - X) =
Trig. Identity
Cos(360)Cos(x) + Sin(360)Sin(x) =>
1CosX + 0Sinx =>
CosX + o =>
CosX
What else can I help you with?
What is sec squared theta times cos squared theta minus tan squared theta?
Tan^2
What is the maximum value of y cos (θ) for values of θ between 720 and 720?
The expression ( y \cos(\theta) ) will have its maximum value when ( \cos(\theta) ) reaches its maximum, which is 1. Since ( \theta ) is constant at 720 degrees, we can calculate ( \cos(720^\circ) ). The angle 720 degrees is equivalent to 0 degrees (since ( 720^\circ - 360^\circ = 360^\circ ), and ( 360^\circ - 360^\circ = 0^\circ )), thus ( \cos(720^\circ) = 1 ). Therefore, the maximum value of ( y \cos(θ) ) is simply ( y ) when ( \theta = 720 ) degrees.
What does negative sine squared plus cosine squared equal?
-Sin^(2)(Theta) + Cos^(2)Theta => Cos^(2)Theta - Sin^(2)Theta Factor (Cos(Theta) - Sin(Theta))( Cos(Theta) + Sin(Theta)) #Is the Pythagorean factors . Or -Sin^(2)Theta = -(1 - Cos^(2)Theta) = Cos(2)Theta - 1 Substitute Cos^(2)Thetqa - 1 + Cos^(2) Theta = 2Cos^(2)Theta - 1
If cos and theta 0.65 what is the value of sin and theta?
You can use the Pythagorean identity to solve this:(sin theta) squared + (cos theta) squared = 1.
How do you integrate cos squared theta times sine theta?
To integrate ( \cos^2 \theta \sin \theta ), you can use a substitution method. Let ( u = \cos \theta ), then ( du = -\sin \theta , d\theta ). The integral becomes ( -\int u^2 , du ), which evaluates to ( -\frac{u^3}{3} + C ). Substituting back, the final result is ( -\frac{\cos^3 \theta}{3} + C ).
What is Cos Theta minus Cos Theta?
Zero. Anything minus itself is zero.
What is cos 90 minus theta?
cosine (90- theta) = sine (theta)
What is sec squared theta times cos squared theta minus tan squared theta?
Tan^2
What is cos theta minus cos theta times sin squared theta?
cos(t) - cos(t)*sin2(t) = cos(t)*[1 - sin2(t)] But [1 - sin2(t)] = cos2(t) So, the expression = cos(t)*cos2(t) = cos3(t)
What is cos theta times cos theta?
Cos theta squared
What is the maximum value of y cos (θ) for values of θ between 720 and 720?
The expression ( y \cos(\theta) ) will have its maximum value when ( \cos(\theta) ) reaches its maximum, which is 1. Since ( \theta ) is constant at 720 degrees, we can calculate ( \cos(720^\circ) ). The angle 720 degrees is equivalent to 0 degrees (since ( 720^\circ - 360^\circ = 360^\circ ), and ( 360^\circ - 360^\circ = 0^\circ )), thus ( \cos(720^\circ) = 1 ). Therefore, the maximum value of ( y \cos(θ) ) is simply ( y ) when ( \theta = 720 ) degrees.
Find all angles in the interval 0 360 satisfying the equation cos theta equals 0.7902?
cos(theta) = 0.7902 arcos(0.7902) = theta = 38 degrees you find complimentary angles
Every angle theta between 0 and 360 degrees for which the ratio of sin theta to cos theta is -3?
108.435 degrees 288.435 degrees (decimal is rounded)
How do you solve theta if cos squared theta equals 1 and 0 is less than or equal to theta which is less than 2pi?
cos2(theta) = 1 so cos(theta) = ±1 cos(theta) = -1 => theta = pi cos(theta) = 1 => theta = 0
How do you simplify tan theta cos theta?
Remember that tan = sin/cos. So your expression is sin/cos times cos. That's sin(theta).
What is cos squared 90 - theta?
The expression (\cos^2(90^\circ - \theta)) can be simplified using the co-function identity, which states that (\cos(90^\circ - \theta) = \sin(\theta)). Therefore, (\cos^2(90^\circ - \theta) = \sin^2(\theta)). This means that (\cos^2(90^\circ - \theta)) is equal to the square of the sine of (\theta).
How do you proof that there is one and only one value of theta makes cos of theta equals 1 true?
You cannot prove it because it is not true! cos(0) = 1 cos(2*pi) = 1 cos(4*pi) = 1 ... cos(2*k*pi) = 1 for all integers k or, if you still work in degrees, cos(0) = 1 cos(360) = 1 cos(720) = 1 ... cos(k*360) = 1 for all integers k
