0
Cos(360 - X) =
Trig. Identity
Cos(360)Cos(x) + Sin(360)Sin(x) =>
1CosX + 0Sinx =>
CosX + o =>
CosX
What else can I help you with?
What is sec squared theta times cos squared theta minus tan squared theta?
Tan^2
What is the maximum value of y cos (θ) for values of θ between 720 and 720?
The expression ( y \cos(\theta) ) will have its maximum value when ( \cos(\theta) ) reaches its maximum, which is 1. Since ( \theta ) is constant at 720 degrees, we can calculate ( \cos(720^\circ) ). The angle 720 degrees is equivalent to 0 degrees (since ( 720^\circ - 360^\circ = 360^\circ ), and ( 360^\circ - 360^\circ = 0^\circ )), thus ( \cos(720^\circ) = 1 ). Therefore, the maximum value of ( y \cos(θ) ) is simply ( y ) when ( \theta = 720 ) degrees.
What does negative sine squared plus cosine squared equal?
To determine what negative sine squared plus cosine squared is equal to, start with the primary trigonometric identity, which is based on the pythagorean theorem...sin2(theta) + cos2(theta) = 1... and then solve for the question...cos2(theta) = 1 - sin2(theta)2 cos2(theta) = 1 - sin2(theta) + cos2(theta)2 cos2(theta) - 1 = - sin2(theta) + cos2(theta)
How do you integrate cos squared theta times sine theta?
To integrate ( \cos^2 \theta \sin \theta ), you can use a substitution method. Let ( u = \cos \theta ), then ( du = -\sin \theta , d\theta ). The integral becomes ( -\int u^2 , du ), which evaluates to ( -\frac{u^3}{3} + C ). Substituting back, the final result is ( -\frac{\cos^3 \theta}{3} + C ).
If cos and theta 0.65 what is the value of sin and theta?
Remember use the Pythagorean Trig/ Identity. Sin^(2)(Theta) + Cos^(2)(Theta) = 1 Algebraically rearrange Sin^(2)(Theta) = 1 - Cos^(2)(Theta) Substitute Sin^(2)(Theta) = 1 - 0.65^(2) Factor Sin^(2)(Theta) = ( 1- 0.65 )( 1 + 0.65) Sin^(2)(Theta) = (0.35)(1.65) Sin^(2)(Theta) = 0.5775 Sin(Theta) = sqrt(0.5775) Sin(Theta) = 0.759934207.... Theta = Sun^(-1)(0.759934207...) Theta = 49.45839813 degrees.
What is Cos Theta minus Cos Theta?
Zero. Anything minus itself is zero.
What is cos 90 minus theta?
cosine (90- theta) = sine (theta)
What is sec squared theta times cos squared theta minus tan squared theta?
Tan^2
What is cos theta minus cos theta times sin squared theta?
cos(t) - cos(t)*sin2(t) = cos(t)*[1 - sin2(t)] But [1 - sin2(t)] = cos2(t) So, the expression = cos(t)*cos2(t) = cos3(t)
What is cos theta times cos theta?
Cos theta squared
What is the maximum value of y cos (θ) for values of θ between 720 and 720?
The expression ( y \cos(\theta) ) will have its maximum value when ( \cos(\theta) ) reaches its maximum, which is 1. Since ( \theta ) is constant at 720 degrees, we can calculate ( \cos(720^\circ) ). The angle 720 degrees is equivalent to 0 degrees (since ( 720^\circ - 360^\circ = 360^\circ ), and ( 360^\circ - 360^\circ = 0^\circ )), thus ( \cos(720^\circ) = 1 ). Therefore, the maximum value of ( y \cos(θ) ) is simply ( y ) when ( \theta = 720 ) degrees.
Find all angles in the interval 0 360 satisfying the equation cos theta equals 0.7902?
cos(theta) = 0.7902 arcos(0.7902) = theta = 38 degrees you find complimentary angles
Every angle theta between 0 and 360 degrees for which the ratio of sin theta to cos theta is -3?
108.435 degrees 288.435 degrees (decimal is rounded)
How do you solve theta if cos squared theta equals 1 and 0 is less than or equal to theta which is less than 2pi?
cos2(theta) = 1 so cos(theta) = ±1 cos(theta) = -1 => theta = pi cos(theta) = 1 => theta = 0
How do you simplify tan theta cos theta?
Remember that tan = sin/cos. So your expression is sin/cos times cos. That's sin(theta).
What is cos squared 90 - theta?
The expression (\cos^2(90^\circ - \theta)) can be simplified using the co-function identity, which states that (\cos(90^\circ - \theta) = \sin(\theta)). Therefore, (\cos^2(90^\circ - \theta) = \sin^2(\theta)). This means that (\cos^2(90^\circ - \theta)) is equal to the square of the sine of (\theta).
How do you proof that there is one and only one value of theta makes cos of theta equals 1 true?
You cannot prove it because it is not true! cos(0) = 1 cos(2*pi) = 1 cos(4*pi) = 1 ... cos(2*k*pi) = 1 for all integers k or, if you still work in degrees, cos(0) = 1 cos(360) = 1 cos(720) = 1 ... cos(k*360) = 1 for all integers k
