How do you integrate 2sinxcosx?

Answer 1

Integrate 2sin(x)cos(x)dx

Let u = cos(x) and du = -sin(x)dx and pull out the -2:

-2[Integral(u*du)]

Integrate with respect to u:

-2(u2)/2 + C

Simplify:

-u2 + C

Replace u with cos(x):

-cos2(x) + C