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X over infinity does not exist but you can predict what it would be as you approach infinity, the limit, so to speak. It should be zero, if it does approach a number.

Q: How much is x over infinity?

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What is the limit as x approaches infinity of the square root of x? Ans: As x approaches infinity, root x approaches infinity - because rootx increases as x does.

the limit [as x-->5] of the function f(x)=2x is 5 the limit [as x-->infinity] of the function f(x) = 2x is infinity the limit [as x-->infinity] of the function f(x) = 1/x is 0 the limit [as x-->infinity] of the function f(x) = -x is -infinity

It is indeterminate. There are many other inderterminate forms. It is not at all the same as 3/3 for example. You can see this with limits and some calculus rules. You must apply the L'Hospital theorem by deriving the numerator and the denominator of the equation that gave you infinity over infinity.-----------------Why ∞/∞ is not 1One could think that ∞/∞ = 1, but this is wrong.The answer depends on the kind of infinity: in fact, there are different kinds of infinity.For example, consider f(x) = x2 and g(x) = x. In the limit x→∞ of the function f(x)/g(x), we havelimx→∞ f(x)/g(x) = limx→∞ x2/x = limx→∞ x = ∞;so, both f(x) and g(x), in that limit, equal infinity, but f(x)/g(x) ≠ 1. If we have f(x) = 2x and g(x) = x, both f(x) and g(x) equal infinity (for x→∞), butlimx→∞ f(x)/g(x) = limx→∞ 2x/x = limx→∞ 2 = 2 ≠ 1.So you see that infinity is something to check everytime!--------------Addition: Since infinity is not a set number, you cannot assume that infinity divided by infinity would equal one. Infinity is an indeterminate number.1To touch on this whatever you take and divide by the same number will always give you one.2Infinity divided by infinity is not equal to 1, But it is undefined, not another infinity. This would help you:First, I am going to define this axiom (assumption) that infinity divided by infinity is equal to one:∞-∞= 1Since ∞ = ∞ + ∞, then we are going to substitute the first infinity in our axiom:∞ + ∞---∞= 1The next step is to split this fraction into two fractions:∞-∞+ ∞-∞= 1Next, substitute the axiom twice into the equation, we get:1 + 1 = 1Finally, this can be rewritten as:2 = 1Therefore, infinity divided by infinity is NOT equal to one. Instead we can get any real number to equal to one when we assume infinity divided by infinity is equal to one, so infinity divided by infinity is undefined.

The log(infinity) does not exist. It is impossible to evaluate because infinity is not a number. When evaluating limits infinity is a special case of a nonexistent limit. The limit of the log(x) as x approaches infinity is infinity because log(x) increases without bound when x gets extremely large.

infinity? Infinity over zero is undefined, or complex infinity depending on numbers you are including in your number system.

Related questions

As x tends towards 0 (from >0), log(x) tend to - infinity. As x tends to + infinity so does log (x), though at a much slower rate.

(x+2)/(x+2) = 1x equals infinity

As X approaches infinity it approaches close as you like to 0. so, sin(-1/2)

Infinity

What is the limit as x approaches infinity of the square root of x? Ans: As x approaches infinity, root x approaches infinity - because rootx increases as x does.

the limit [as x-->5] of the function f(x)=2x is 5 the limit [as x-->infinity] of the function f(x) = 2x is infinity the limit [as x-->infinity] of the function f(x) = 1/x is 0 the limit [as x-->infinity] of the function f(x) = -x is -infinity

infinity x 2

This browser is not much use when it comes to mathematics but I'll try.Suppose X is a random variable with a Normal distribution and let f(x) be the probability density function of x.Then the mean is mu = E(X) = Integral of x*f(x) dx over the domain of X [which is negative infinity to positive infinity].The variance is E{[X - E(X)]2} = Integral of (x - mu)2*f(x) dx over the domain of X.

Infinity Explanation: a x infinity = infinity, if a greater than 1 In given case, a = 2 Therefore, 2 x infinity = infinity Hope this helps :) Your Fellow, Another Indian Kid

It depends. The determining factor is whether the numerator goes to infinity faster or slower than the denominator. If the numerator goes faster, then the answer is infinity. For example, as x goes to infinity, exp(x)/x goes to infinity. If the numerator goes slower, then the answer is zero. For example, as x goes to infinity, x/exp(x) goes to zero. If they go at the same rate, then the answer is intermediate. For example, 2x/x is 2 for all x, including when x goes to infinity.

An unknown number x times infinity would be infinity.

It is indeterminate. There are many other inderterminate forms. It is not at all the same as 3/3 for example. You can see this with limits and some calculus rules. You must apply the L'Hospital theorem by deriving the numerator and the denominator of the equation that gave you infinity over infinity.-----------------Why ∞/∞ is not 1One could think that ∞/∞ = 1, but this is wrong.The answer depends on the kind of infinity: in fact, there are different kinds of infinity.For example, consider f(x) = x2 and g(x) = x. In the limit x→∞ of the function f(x)/g(x), we havelimx→∞ f(x)/g(x) = limx→∞ x2/x = limx→∞ x = ∞;so, both f(x) and g(x), in that limit, equal infinity, but f(x)/g(x) ≠ 1. If we have f(x) = 2x and g(x) = x, both f(x) and g(x) equal infinity (for x→∞), butlimx→∞ f(x)/g(x) = limx→∞ 2x/x = limx→∞ 2 = 2 ≠ 1.So you see that infinity is something to check everytime!--------------Addition: Since infinity is not a set number, you cannot assume that infinity divided by infinity would equal one. Infinity is an indeterminate number.1To touch on this whatever you take and divide by the same number will always give you one.2Infinity divided by infinity is not equal to 1, But it is undefined, not another infinity. This would help you:First, I am going to define this axiom (assumption) that infinity divided by infinity is equal to one:∞-∞= 1Since ∞ = ∞ + ∞, then we are going to substitute the first infinity in our axiom:∞ + ∞---∞= 1The next step is to split this fraction into two fractions:∞-∞+ ∞-∞= 1Next, substitute the axiom twice into the equation, we get:1 + 1 = 1Finally, this can be rewritten as:2 = 1Therefore, infinity divided by infinity is NOT equal to one. Instead we can get any real number to equal to one when we assume infinity divided by infinity is equal to one, so infinity divided by infinity is undefined.