X over infinity does not exist but you can predict what it would be as you approach infinity, the limit, so to speak. It should be zero, if it does approach a number.
What is the limit as x approaches infinity of the square root of x? Ans: As x approaches infinity, root x approaches infinity - because rootx increases as x does.
the limit [as x-->5] of the function f(x)=2x is 5 the limit [as x-->infinity] of the function f(x) = 2x is infinity the limit [as x-->infinity] of the function f(x) = 1/x is 0 the limit [as x-->infinity] of the function f(x) = -x is -infinity
It is indeterminate. There are many other inderterminate forms. It is not at all the same as 3/3 for example. You can see this with limits and some calculus rules. You must apply the L'Hospital theorem by deriving the numerator and the denominator of the equation that gave you infinity over infinity.-----------------Why ∞/∞ is not 1One could think that ∞/∞ = 1, but this is wrong.The answer depends on the kind of infinity: in fact, there are different kinds of infinity.For example, consider f(x) = x2 and g(x) = x. In the limit x→∞ of the function f(x)/g(x), we havelimx→∞ f(x)/g(x) = limx→∞ x2/x = limx→∞ x = ∞;so, both f(x) and g(x), in that limit, equal infinity, but f(x)/g(x) ≠ 1. If we have f(x) = 2x and g(x) = x, both f(x) and g(x) equal infinity (for x→∞), butlimx→∞ f(x)/g(x) = limx→∞ 2x/x = limx→∞ 2 = 2 ≠ 1.So you see that infinity is something to check everytime!--------------Addition: Since infinity is not a set number, you cannot assume that infinity divided by infinity would equal one. Infinity is an indeterminate number.1To touch on this whatever you take and divide by the same number will always give you one.2Infinity divided by infinity is not equal to 1, But it is undefined, not another infinity. This would help you:First, I am going to define this axiom (assumption) that infinity divided by infinity is equal to one:∞-∞= 1Since ∞ = ∞ + ∞, then we are going to substitute the first infinity in our axiom:∞ + ∞---∞= 1The next step is to split this fraction into two fractions:∞-∞+ ∞-∞= 1Next, substitute the axiom twice into the equation, we get:1 + 1 = 1Finally, this can be rewritten as:2 = 1Therefore, infinity divided by infinity is NOT equal to one. Instead we can get any real number to equal to one when we assume infinity divided by infinity is equal to one, so infinity divided by infinity is undefined.
The log(infinity) does not exist. It is impossible to evaluate because infinity is not a number. When evaluating limits infinity is a special case of a nonexistent limit. The limit of the log(x) as x approaches infinity is infinity because log(x) increases without bound when x gets extremely large.
There is no number greater than infinity. Infinity is defined to be greater than any number, so there can not be two numbers, both infinity, that are different.However, when dealing with limits, one can approach a non-infinite value for a function involving infinity. Take, for example, 2x divided by x, when x is infinity. That value is indeterminate, because infinity divided by infinity is defined as indeterminate, and 2 times infinity is still infinity.But, if you look at the limit of 2x divided by x, as x approaches infinity, you do get a value, and that value is 2. This does not mean that 2x when x is infinity is twice infinity, it just means that, right before x becomes infinity, the ratio is right before 2.Infinity should not be thought of as a number, but rather as a direction. Whereas a number represents a specific quantity, infinity does not define given quantity. (If you started counting really fast for billions of years, you would never get to infinity.) There are, however, different "sizes of infinity." Aleph-null, for example, is the infinity that describes the size of the natural numbers (0,1,2,3,4....) The infinity that describes the size of the real numbers is much larger than aleph-null, for between any two natural numbers, there are infinite real numbers.Anyway, to improve upon the answer above, it is not meaningful to say "when x is infinity," because, as explained above, no number can "be" infinity. A number can approach infinity, that is to say, get larger and larger and larger, but it will never get there. Because infinity is not a number, there is no point in asking what number is more than infinity.
As x tends towards 0 (from >0), log(x) tend to - infinity. As x tends to + infinity so does log (x), though at a much slower rate.
(x+2)/(x+2) = 1x equals infinity
As X approaches infinity it approaches close as you like to 0. so, sin(-1/2)
This browser is not much use when it comes to mathematics but I'll try.Suppose X is a random variable with a Normal distribution and let f(x) be the probability density function of x.Then the mean is mu = E(X) = Integral of x*f(x) dx over the domain of X [which is negative infinity to positive infinity].The variance is E{[X - E(X)]2} = Integral of (x - mu)2*f(x) dx over the domain of X.
infinity x 2
What is the limit as x approaches infinity of the square root of x? Ans: As x approaches infinity, root x approaches infinity - because rootx increases as x does.
the limit [as x-->5] of the function f(x)=2x is 5 the limit [as x-->infinity] of the function f(x) = 2x is infinity the limit [as x-->infinity] of the function f(x) = 1/x is 0 the limit [as x-->infinity] of the function f(x) = -x is -infinity
Infinity
Infinity Explanation: a x infinity = infinity, if a greater than 1 In given case, a = 2 Therefore, 2 x infinity = infinity Hope this helps :) Your Fellow, Another Indian Kid
It depends. The determining factor is whether the numerator goes to infinity faster or slower than the denominator. If the numerator goes faster, then the answer is infinity. For example, as x goes to infinity, exp(x)/x goes to infinity. If the numerator goes slower, then the answer is zero. For example, as x goes to infinity, x/exp(x) goes to zero. If they go at the same rate, then the answer is intermediate. For example, 2x/x is 2 for all x, including when x goes to infinity.
An unknown number x times infinity would be infinity.
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