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If y varies inversely as the square of x and y equals 5 when x equals 2.5 what is the value of y when x equals 9?
Wiki User
∙ 9y ago
So 5 = (xy)^2 and x = 2.5. This means that 5 = (2.5y)^2. So sqrt(5)/2.5 = y when x = 2.5. Now if x = 9 then 5 = (9y)^2. So sqrt(5)/9 = y. This means that for any x in this relation y = sqrt(5)/x.
Wiki User
∙ 9y ago
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