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If we assume a constant inverse relationship then we can start with the equation y = c/x where c is the constant of proportionality. Plugging in the known values of x = 7 and y = 5 we determine that c = 35. We now have the equation of y = 35/x. Plugging in 4 for x we see that y = 35/4 = 8.75.

Q: If y varies inversely with x and y equals 5 when x equals 7what is the value of y when x equals 4?

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3k-5=7k+73k-7k=7+5-4k=12k=-3

z = 8/3.

We write y=kx since y varies directly as x. Now we know if x is 5, y is 10. so we write 10=5k so k=2

the value of log (log4(log4x)))=1 then x=

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3k-5=7k+73k-7k=7+5-4k=12k=-3

If y and x are related inversely, then the equation for y can be said to be:y = k/xTo find the constant k, substitute 12 for y and 6 for x (a pair of values that are known to satisfy the equation).y = k/x12 = k/612 X 6 = k72 = kThe value of the variation constant k is 72.

z = 8/3.

So 5 = (xy)^2 and x = 2.5. This means that 5 = (2.5y)^2. So sqrt(5)/2.5 = y when x = 2.5. Now if x = 9 then 5 = (9y)^2. So sqrt(5)/9 = y. This means that for any x in this relation y = sqrt(5)/x.

Power factor value varies from zero to one depending upon the angle between vectorial value of voltage & current and equals to cos fi ( where fi is the angle between i & v)

Power factor value varies from zero to one depending upon the angle between vectorial value of voltage & current and equals to cos fi ( where fi is the angle between i & v)

We write y=kx since y varies directly as x. Now we know if x is 5, y is 10. so we write 10=5k so k=2

Power factor value varies from zero to one depending upon the angle between vectorial value of voltage & current and equals to cos fi ( where fi is the angle between i & v)

56, 55, 54, 53, 52, 51, 50

x*y = k where k is a constant.When x = 9, y = 7 so k = 9*7 = 63 When x = 21, 21*y = 63 so y = 3.

If one value of a variable increases as another value of a different variable decreases in a mathematical equation, they are said to be inversely proportional or vary inversely. For example, the strength of the force of gravity decreases as the square of the interacting distance increases, so the strength of gravity is inversely proportional to the square of the distance, or strength âˆ 1/distance2.