If we assume a constant inverse relationship then we can start with the equation y = c/x where c is the constant of proportionality. Plugging in the known values of x = 7 and y = 5 we determine that c = 35. We now have the equation of y = 35/x. Plugging in 4 for x we see that y = 35/4 = 8.75.
3
3k-5=7k+73k-7k=7+5-4k=12k=-3
z = 8/3.
We write y=kx since y varies directly as x. Now we know if x is 5, y is 10. so we write 10=5k so k=2
the value of log (log4(log4x)))=1 then x=
3
3k-5=7k+73k-7k=7+5-4k=12k=-3
If y and x are related inversely, then the equation for y can be said to be:y = k/xTo find the constant k, substitute 12 for y and 6 for x (a pair of values that are known to satisfy the equation).y = k/x12 = k/612 X 6 = k72 = kThe value of the variation constant k is 72.
z = 8/3.
So 5 = (xy)^2 and x = 2.5. This means that 5 = (2.5y)^2. So sqrt(5)/2.5 = y when x = 2.5. Now if x = 9 then 5 = (9y)^2. So sqrt(5)/9 = y. This means that for any x in this relation y = sqrt(5)/x.
Power factor value varies from zero to one depending upon the angle between vectorial value of voltage & current and equals to cos fi ( where fi is the angle between i & v)
Power factor value varies from zero to one depending upon the angle between vectorial value of voltage & current and equals to cos fi ( where fi is the angle between i & v)
We write y=kx since y varies directly as x. Now we know if x is 5, y is 10. so we write 10=5k so k=2
Power factor value varies from zero to one depending upon the angle between vectorial value of voltage & current and equals to cos fi ( where fi is the angle between i & v)
56, 55, 54, 53, 52, 51, 50
x*y = k where k is a constant.When x = 9, y = 7 so k = 9*7 = 63 When x = 21, 21*y = 63 so y = 3.
The value of the impulse equals the the force times the time.