0.5*(402-120) = 740 diagonals
For an n-sided polygon, the number of diagonals is 1+2+3+....+(n-4)+2(n-3). For a nine-sided polygon, there are 1+2+3+4+5+2(6)=27 diagonals.
50*(50 - 3)/2 = 1175 diagonals.
Heptagon
The formula is: 0.5*(n2-3n) where n is the number of sides of the polygon. So: 0.5*(81-27) = 27 diagonals
In a 54-sided polygon, 53 possible diagonals can be drawn from one vertex to another. These diagonals will not intersect. Therefore, the interior will be divided into 54 regions by the 53 diagonals plus the two sides of the original polygon that adjoin the vertex from which the diagonals are drawn.
A normal convex polygon cannot have 15 diagonals. If it has n sides, it has n*(n-3)/2 diagonals and this is equal to 15 if n = 7.18. However, it is not possible for a polygon to have a fractional side.
There is no such polygon that has 95 diagonals because a 15 sided polygon has 90 diagonals and a 16 sided polygon has 104 diagonals.
A polygon that has 104 diagonals will have 16 sides
That polygon is called a "triangle". It has no diagonals.
There are 90 diagonals in a 15-sided polygon.
An 11 sided polygon has 44 diagonals.
A four-sided polygon has two diagonals.
You can use the formula D=S-2 where D is the number of possible diagonals and S is the number of sides the polygon has.
No
a convex polygon
how many diagonals are there iin a polygon of 11 sides