0.5*(n2-3n) where n is equal to the number of sides of the polygon
The formula is: 0.5*(n2-3n) = diagonals whereas n is the number of sides of the polygon
A polygon with 14 diagonals will have 7 sides
209
A normal convex polygon cannot have 15 diagonals. If it has n sides, it has n*(n-3)/2 diagonals and this is equal to 15 if n = 7.18. However, it is not possible for a polygon to have a fractional side.
0.5*(n2-3n) where n is equal to the number of sides of the polygon
A 7 sided polygon has 14 diagonals
Number of diagonals = 1/2*(n2-3n) where n = the number of sides of the polygon.
38 diagonals
It has 20 diagonals
It is: 0.5*(n2-3n) = diagonals whereas n is the number of sides of the polygon
The formula is: 0.5*(n2-3n) = diagonals whereas n is the number of sides of the polygon
A polygon with 14 diagonals will have 7 sides
11
209
The equation is: 0.5*(n2-3n) = diagonals whereas n is the number of sides of the polygon
There is no such polygon that fits the given information.