the answer is: (y-b)/x = m y = mx + b y - b = mx (y-b)/x = m
The x in y=mx+b is the independent variable. You could solve for x, making this a function of y, with simple algebra. y = mx + b y - b = mx (y-b)/m = x
It is the intercept: the value that y takes when x = 0
It's 2. your equation is y=mx+b, so the gradient, or slope, is the "m" in the equation.
If the equation Y = mX + b is graphed on standard Cartesian orthogonal x-y coordinates, then: -- the graph is a straight line -- 'm' is the slope of the line -- 'b' is the Y-intercept, i.e. the number where the line crosses the Y-axis, i.e. the value of 'Y' when X = 0 .
An algebraic equation is a mathematical equation in which one or both sides is an algebraic expression.
how can we convert algebraic expression into QBASIC a square + b square i = pTR/100 2xy mx+c a=r square a+b
If you mean: mx+b = y then it is the formula of a straight line whereas m is the slope and b is the y intercept
If y = mx + b, then x = (y-b)/m (for m not equal to zero).
The x-intercept is equal to -b/m.
In the equation y = mx + b, x is the independent variable.Also, m is the slope, b is the y-intercept, and y is the dependent variable.
yes
same thing. but its easy to change y=b+mx to y=mx+b
y = mx + b y - mx = b
Just subtract y from both sides. 'm' becomes 'A', 'b' becomes 'C' and 'B' will be equal to one.
y=mx+b mx+b=y (mx means multipy.) Hope this helps! -natali4everca
b = y - mx.