The expression in the question "y -2x" is not a function.
For example, the derivate of x2 is 2x; then, an antiderivative of 2x is x2. That is to say, you need to find a function whose derivative is the given function. The antiderivative is also known as the indifinite integral. If you can find an antiderivative for a function, it is fairly easy to find the area under the curve of the original function - i.e., the definite integral.
The [ 2x + 1 ] represents a function of 'y' .
It is: 2x^2 -x -21
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The expression in the question "y -2x" is not a function.
That doesn't factor neatly. Applying the quadratic equation, we find two imaginary solutions: 1 plus or minus i times the square root of 2x = 2.4142135623730951ix = 0.4142135623730951iwhere i is the square root of -1
y = 2x + 5x - 12 = 7x - 12 So the zero is 12/7 = 1.7143 (approx)
2x^2 + 3x - 20 = 0 is 2x^2 + 8x - 5x -20 = 0 is 2x(x + 4) -5(x + 4) = 0 is (2x - 5)(x +4) = 0 Hence 2x -5 = 0 which gives x = 2.5 or x + 4 = 0 which gives x = -4
Whether or not a function has zeros depends on the domain over which it is defined.For example, the linear equation 2x = 3 has no zeros if the domain is the set of integers (whole numbers) but if you allow rational numbers then x = 1.5 is a zero.A quadratic function such as x^2 = 2 has no rational zeros, but it does have irrational zeros which are sqrt(2) and -sqrt(2).Similarly, a quadratic equation need not have real zeros. It will have zeros if the domain is extended to the complex field.In the coordinate plane, a quadratic without zeros will either be wholly above the horizontal axis or wholly below it.
To integrate a function you find what the function you have is the derivative of. for example the derivative of x^2 is 2x. so the integral of 2x is x^2.
2x-3=10x+21 2x-3-2x=10x+21-2x -3=8x+21 -3-21=8x+21-21 -24=8x -3=x
The domain of the function 1/2x is {0, 2, 4}. What is the range of the function?
2x-21 = 7 Adding 21 in both sides will change 2x-21+21 = 7 + 21 into 2x = 28 Now divide both sides on 2 2x/2 = 28/2 then x = 14
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Let's represent the number as "x". The given equation can be written as 2x - 12 = 30. Adding 12 to both sides, we get 2x = 42. Finally, dividing both sides by 2, we find that x = 21. So, the number is 21.
For example, the derivate of x2 is 2x; then, an antiderivative of 2x is x2. That is to say, you need to find a function whose derivative is the given function. The antiderivative is also known as the indifinite integral. If you can find an antiderivative for a function, it is fairly easy to find the area under the curve of the original function - i.e., the definite integral.