Some functions are only defined for certain values of the argument. For example, the the logarithm is defined for positive values. The inverse function is defined for all non-zero numbers. Sometimes the range determines the domain. If you are restricted to the real numbers, then the domain of the square root function must be the non-negative real numbers. In this way, there are definitional domains and ranges. You can then chose any subset of the definitional domain to be your domain, and the images of all the values in the domain will be the range.
y = 1/x
sqrt(x) Domain: {0,infinity) Range: {0,infinity) *note: the domain and range include the point zero.
x = the domain y = the co-domain and range is the output or something e_e
The domain and the range depends on the context. For example, the domain and the range can be the whole of the complex field. Or I could define the domain as {-2, 1, 5} and then the range would be {0, 3, -21}. When either one of the range and domain is defined, the other is implied.
true
True.
True.
The domain and range of the composite function depend on both of the functions that make it up.
Domain and range are used when you deal with functions - so basically you use them whenever you deal with functions.
true
The doman can extend from negative infinioty to positive infinity. Its range is from (+)1 to (-)1.
true
Which equation can have the following domain and range? {x | 8 ≤ x ≤ 14} {y | 29 ≤ y ≤ 53}Answer this question…
The inverse of the inverse is the original function, so that the product of the two functions is equivalent to the identity function on the appropriate domain. The domain of a function is the range of the inverse function. The range of a function is the domain of the inverse function.
Yes, for some functions A, and not for others.
All functions are relations with the condition that each element of the domain is paired with only one element of the range. A relation is any pairing of numbers from the domain to the range.