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The domain and range of the composite function depend on both of the functions that make it up.

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Q: When you compose two functions the domain and the range of the original function does influence the domain and the range of their composition?

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Of the three functions, all three pass the vertical line test. That is, if you draw a vertical line anywhere on the graph that the function is, that line will only pass through the function once. All three are also invertible functions, which means that there is a function that is capable of "undoing" the original function. And because the functions all pass the vertical line test, they are all able to be differentiated.

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The inverse of the inverse is the original function, so that the product of the two functions is equivalent to the identity function on the appropriate domain. The domain of a function is the range of the inverse function. The range of a function is the domain of the inverse function.

When graphing functions, an inverse function will be symmetric to the original function about the line y = x. Since a constant function is simply a straight, horizontal line, its inverse would be a straight, vertical line. However, a vertical line is not a function. Therefore, constant functions do not have inverse functions. Another way of figuring this question can be achieved using the horizontal line test. Look at your original function on a graph. If any horizontal line intersects the graph of the original function more than once, the original function does not have an inverse. The constant function is a horizontal line. Under the assumptions of the horizontal line test, a horizontal line infinitely will cross the original function. Thus, the constant function does not have an inverse function.

When a function calls itself it is called as direct recursion. A function calls other functions which eventually call the original function is called as indirect recursion.

Of the three functions, all three pass the vertical line test. That is, if you draw a vertical line anywhere on the graph that the function is, that line will only pass through the function once. All three are also invertible functions, which means that there is a function that is capable of "undoing" the original function. And because the functions all pass the vertical line test, they are all able to be differentiated.

Maybe; the range of the original function is given, correct? If so, then calculate the range of the inverse function by using the original functions range in the original function. Those calculated extreme values are the range of the inverse function. Suppose: f(x) = x^3, with range of -3 to +3. f(-3) = -27 f(3) = 27. Let the inverse function of f(x) = g(y); therefore g(y) = y^(1/3). The range of f(y) is -27 to 27. If true, then f(x) = f(g(y)) = f(y^(1/3)) = (y^(1/3))^3 = y g(y) = g(f(x)) = g(x^3) = (x^3)^3 = x Try by substituting the ranges into the equations, if the proofs hold, then the answer is true for the function and the range that you are testing. Sometimes, however, it can be false. Look at a transcendental function.

The original function's RANGE becomes the inverse function's domain.

Grammy Award for Best Original Jazz Composition was created in 1967.