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A parabola with vertex (h, k) has equation of the form:

y = a(x - h)² + k

→ vertex (k, h) = (3, 5), and a point on it is (-1, 6)

→ 6 = a(-1 - 3)² + 5

→ 6 = a(-4)² + 5

→ 1 = 16a

→ a = 1/16

→ The coefficient of the x² term is 1/16

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โˆ™ 2016-08-31 08:14:06
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Q: What is the coefficient of the squared term in the parabola's equation when the vertex is at 3 5 and the point -1 6 is on it?
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