Suppose the length is L cmThen the width is 2L - 8 cm
Therefore, the area is L*W = L*(2L - 8) = 2L^2 - 8L sq cm.
Then 2L^2 - 8L = 28
or 2L^2 - 8L - 28 = 0
that is L^2 - 4L - 14 = 0
therefore L = 2+3*sqrt(2) [the other root of the quadratic equation is negative and so cannot be a length].
and then W = 6*sqrt(2) - 4
By Pythagoras,
L^2 = 4 + 9*2 + 12*sqrt(2) = 22 + 12*sqrt(2)
W^2 = 36*2 + 16 - 48*sqrt(2) = 88 - 48*sqrt(2)
and then D^2 = L^2 + W^2 = 110 - 36*sqrt(2) = 59.0883 approx
and so D = 7.6869 cm, approx.
I think it's 12x square.
Suppose the length is L cmThen the width is 2L - 2 cmTherefore, the area is L*W = L*(2L - 2) = 2L^2 - 2L sq cm.Then 2L^2 - 2L = 161or 2L^2 - 2L - 161 = 0therefore L = [1+sqrt(323)]/2 [the other root of the quadratic equation is negative and so cannot be a length].and then W = sqrt(323) - 1By Pythagoras,L^2 = 1/4 + 1/4*323 + sqrt(323)/4 = 81 + sqrt(323)/2W^2 = 323 + 1 - 2*sqrt(323) = 324 - 2*sqrt(323)and then D^2 = L^2 + W^2 = 405 - 3/2*sqrt(323) = 378.0417 approxand so D = 19.4433 cm, approx.
The formula is:Volume = 0Flat 2-dimensional figures don't have volume. In other words, they can't hold water. A figure is 2-dimensional if it can be drawn on paper.A rectangle has area ... the amount of space it covers on paper or on the ground.The formula for the area of a rectangle isArea = (Length) x (Width)
The perimeter is the distance around a shape, If the dimensions given describe a rectangle with length of 8cm and width of 6cm, the perimeter would be 2(L + W), which means the length and width are added together and multiplied by 2. Hence. 8 + 6 = 14 X 2 = 28cm perimeter.
Suppose the length and width of the rectangle are L and W metres respectively.Then the perimeter, P = 20 m implies that2(L + W ) = 20 => L + W = 10 or W = 10 - L.Then Area = L * W = L * (10 - L) sq metres.
The width will be 30cm
If the length of a rectangle is twice its width and it has a perimeter of 48, then the rectangle is 16 in length and 8 in width.
The diagonal is 26cm
The length of a rectangle that has a diagonal of 25 feet and a width of 15 feet is 20 feet.
Width is 5.
The length of the diagonal is about 16.03 feet.
The diagonal of a rectangle with the length of 89.5 inches and a width of 48 inches is approximately 101.6 inches.
The length of a rectangle is twice its width. If the perimeter of the rectangle is , find its area.
The diagonal is 20.
The diagonal length is about 18.44 inches.
The diagonal of a rectangle with the length of 30 yd and the width of 30 yd is approximately 42.43 yd
Diagonal = 10 meters.