Suppose the length is L cmThen the width is 2L - 2 cm
Therefore, the area is L*W = L*(2L - 2) = 2L^2 - 2L sq cm.
Then 2L^2 - 2L = 161
or 2L^2 - 2L - 161 = 0
therefore L = [1+sqrt(323)]/2 [the other root of the quadratic equation is negative and so cannot be a length].
and then W = sqrt(323) - 1
By Pythagoras,
L^2 = 1/4 + 1/4*323 + sqrt(323)/4 = 81 + sqrt(323)/2
W^2 = 323 + 1 - 2*sqrt(323) = 324 - 2*sqrt(323)
and then D^2 = L^2 + W^2 = 405 - 3/2*sqrt(323) = 378.0417 approx
and so D = 19.4433 cm, approx.
Suppose the length is L cmThen the width is 2L - 8 cmTherefore, the area is L*W = L*(2L - 8) = 2L^2 - 8L sq cm.Then 2L^2 - 8L = 28or 2L^2 - 8L - 28 = 0that is L^2 - 4L - 14 = 0therefore L = 2+3*sqrt(2) [the other root of the quadratic equation is negative and so cannot be a length].and then W = 6*sqrt(2) - 4By Pythagoras,L^2 = 4 + 9*2 + 12*sqrt(2) = 22 + 12*sqrt(2)W^2 = 36*2 + 16 - 48*sqrt(2) = 88 - 48*sqrt(2)and then D^2 = L^2 + W^2 = 110 - 36*sqrt(2) = 59.0883 approxand so D = 7.6869 cm, approx.
y=2x
2(xy)
twice as much as whatever 'E' happens to be at the moment
(x^2-14x+49)
You draw a rectangle that has a diagonal which length is equal to twice the length of the side of the square.
2x4
98 square feet
For a rectangle, calculate twice the length, plus twice the width.For a rectangle, calculate twice the length, plus twice the width.For a rectangle, calculate twice the length, plus twice the width.For a rectangle, calculate twice the length, plus twice the width.
The width is 6 cm and the length is 12 cm.
The length of a rectangle is twice its width. If the perimeter of the rectangle is , find its area.
If the circle is inscribed in the square, the side length of the square is the same as the diameter of the circle which is twice its radius: → area_square = (2 × 5 in)² = 10² sq in = 100 sq in If the circle circumscribes the square, the diagonal of the square is the same as the diameter of the circle; Using Pythagoras the length of the side of the square can be calculated: → diagonal = 2 × 5 in = 10 in → side² + side² = diagonal² → 2 × side² = diagonal² → side² = diagonal² / 2 → side = diagonal / √2 → side = 10 in / √2 → area _square = (10 in / √2)² = 100 sq in / 2 = 50 sq in.
If the length of a rectangle is twice its width and it has a perimeter of 48, then the rectangle is 16 in length and 8 in width.
4 cm
It is: 10 times 5 = 50 square in
The rectangle is 12 units by 3 units.
9" x 4"