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If that is x^2-2x-15=0, then you would have to complete the square.

Divide the -2 from the single x by 2 to get -1, then square that to get 1. Then you would add 1 to both sides like so -> (x^2-2x+1)-15=1

Then you would factor (x^2-2x+1) to (x-1)^2 and then substitute.

Like so -> (x-1)^2 -15=1

Then add 15 to each side -> (x-1)^2=16

Then take the square root of both sides -> x-1 = plus or minus 4

Then solve for both negative and positive number -> x = -3 and x = 5

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Q: What are the solutions to the equation x2-2x-15 equals 0?
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