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If that is x^2-2x-15=0, then you would have to complete the square.
Divide the -2 from the single x by 2 to get -1, then square that to get 1. Then you would add 1 to both sides like so -> (x^2-2x+1)-15=1
Then you would factor (x^2-2x+1) to (x-1)^2 and then substitute.
Like so -> (x-1)^2 -15=1
Then add 15 to each side -> (x-1)^2=16
Then take the square root of both sides -> x-1 = plus or minus 4
Then solve for both negative and positive number -> x = -3 and x = 5
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What is the radical equation 4 equals x2-2-x?
It is a quadratic equation and can be rearranged in the form of:- x2-x-6 = 0 (x+2)(x-3) = 0 Solutions: x = -2 and x = 3
What are the solutions for the quadratic equation x2 plus 6x equals 16?
x2 + 6x = 16=> x2 + 6x - 16 = 0=> x2 + 8x -2x - 16 = 0=> (x+8)(x-2) = 0=> x = -8 or x = 2So, the solutions of the quadratic equation x2 + 6x = 16 are -8 and 2.
How do you solve 3x2 x-4 equals 0?
3x2+x-4 = 0 (3x+4)(x-1) = 0 Solutions: x = 1 and x = -4/3 By using the quadratic equation formula.
What values best approximate the solutions of -4x2 plus 7x plus 5 equals 0?
Using the quadratic equation formula:- x = -0.5447270865 or x = 2.294727086
What is the quadratic of this equation x2 plus 11x plus 11 equals 7x plus 9?
x2+11x+11 = 7x+9 x2+11x-7x+11-9 = 0 x2+4x+2 = 0 The above quadratic equation can be solved by using the quadratic equation formula and it will have two solutions.
