0
If that is x^2-2x-15=0, then you would have to complete the square.
Divide the -2 from the single x by 2 to get -1, then square that to get 1. Then you would add 1 to both sides like so -> (x^2-2x+1)-15=1
Then you would factor (x^2-2x+1) to (x-1)^2 and then substitute.
Like so -> (x-1)^2 -15=1
Then add 15 to each side -> (x-1)^2=16
Then take the square root of both sides -> x-1 = plus or minus 4
Then solve for both negative and positive number -> x = -3 and x = 5
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