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If that is x^2-2x-15=0, then you would have to complete the square.
Divide the -2 from the single x by 2 to get -1, then square that to get 1. Then you would add 1 to both sides like so -> (x^2-2x+1)-15=1
Then you would factor (x^2-2x+1) to (x-1)^2 and then substitute.
Like so -> (x-1)^2 -15=1
Then add 15 to each side -> (x-1)^2=16
Then take the square root of both sides -> x-1 = plus or minus 4
Then solve for both negative and positive number -> x = -3 and x = 5
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What is the radical equation 4 equals x2-2-x?
It is a quadratic equation and can be rearranged in the form of:- x2-x-6 = 0 (x+2)(x-3) = 0 Solutions: x = -2 and x = 3
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x2 + 6x = 16=> x2 + 6x - 16 = 0=> x2 + 8x -2x - 16 = 0=> (x+8)(x-2) = 0=> x = -8 or x = 2So, the solutions of the quadratic equation x2 + 6x = 16 are -8 and 2.
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Using the quadratic equation formula:- x = -0.5447270865 or x = 2.294727086
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